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2 years ago

Are parallelogram rectangles

Mathematics

1 answer:

Andreyy892 years ago

7 0

Yes if they have equal sides

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Please help and choose letter choice

Orlov [11]

The correct answer is a

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2 years ago

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A researcher is testing a hypothesis of a single mean. The critical z value for a = .05 and a two‑tailed test is +1.96. The obse

grandymaker [24]

Answer:

The decision made by the researcher based on this information is to reject the null hypothesis.

Step-by-step explanation:

Two-tailed hypothesis test:

Critical value: $z_c$

Test statistic: z

If $|z| < |z_c|$ , we do not reject the null hypothesis.

If $|z| > |z_c|$ , we reject the null hypothesis.

In this question:

$z_c = 1.96, z = -2.05, |z| = 2.05$

Since $|z| > |z_c|$ , we reject the null hypothesis.

The decision made by the researcher based on this information is to reject the null hypothesis.

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2 years ago

Which equation describes the graph? (In the photo)

maw [93]

Answer:

C. The slope is 3 and the y-intercept is -3

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2 years ago

On a test of 80 items, Ariel got 59 correct. What percent were correct? a. 73. 75% c. 135. 59322% b. 1. 3559322% d. 0. 7375%.

Mila [183]

you divide 59% from 80 and is 7375=73

3 0

1 year ago

Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)

Gnom [1K]

Answer: Horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

Step-by-step explanation:

Since we have given that

$y=\dfrac{x^2-9}{4x^2+1}$

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is $4x^2+1$

Now,

$4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}$

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

$y=\dfrac{1}{4}$

Hence, horizontal asymptote is $\dfrac{1}{4}$ and vertical asymptotes are $\pm \dfrac{1}{2i}$

8 0

2 years ago