Find the equation of the line passing through (4,1) and perpendicular to the line whose equation is 1x-3y-4=0
1 answer:
9514 1404 393
Answer:
3x +y -13 = 0
Step-by-step explanation:
The perpendicular line will have the variable coefficients swapped and one of them negated. The new constant will be appropriate to the given point.
3(x -4) +1(y -1) = -0
3x +y -13 = 0
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<em>Additional comment</em>
The given equation is in "general form", so that is the form of the equation we have given as the answer. This form is convenient in that the general form equation for a line through the origin, ax+by=0, is easily translated to make it pass through a point (h, k): a(x -h) +b(y -k) = 0. Eliminating parentheses puts the equation back into general form.
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