<span>If "m" balls are thrown per second, the time taken for a ball to reach its maximum height will be 1/m seconds. How to get this? See that the next ball is thrown only when the previous ball reaches its maximum height. If 'm' balls were thrown in 1 second this means that each ball was attaining its maximum ht in 1/m seconds.
This was the main part. Now we can proceed to find maximum height in 2 ways-
a)
We know for upward journey ,
t=1/m
a=-g
v=u-gt
final velocity ,v = 0 (at highest point)
u
=gt = g/m
Now we can apply
h=ut-1/2 gt^2
Putting the values of u,t, we will get
h= g/2m^2
b)
The second method uses a trick that time taken to reach the maximum ht is same as time taken to fall down.
So, we will now consider the downward journey of ball which also takes 1/m seconds
We apply
h=ut+1/2gt^2
Here u=0 ,t=1/m
We will again get ,
h=g/2m^2</span>
Answer:
La aceleración total de la piedra es 2,85 m/s².
Explanation:
La aceleracion total de la piedra viene dado por la suma de la acelaración centrípeta y de aceleración tangencial, como:
La aceleración tangencial () es la aceleracion del cilindro igua a:
Entonces, la aceleración centrípeta es:
En donde:
v: es la velocidad tangencial de la piedra = 2,0 m/s
r: es el radio del cilindro = 1,5 m
Finalmente, el módulo de la aceleración total es:
Por lo tanto la aceleración total de la piedra es 2,85 m/s².
Espero que te sea de utilidad!
The concept that underlies the other would be :
effective nuclear charge zeff
It control Ip and electron affinity by determining attractive force between atom and the electron
it underlies atomic size because it draws the valence electron closer
hope this helps