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3 years ago

A cannon shoot a cannon ball. The momentum compared to the cannon ball is

Physics

1 answer:

worty [1.4K]3 years ago

8 0

Answer:

After the firing occurs, both the cannon and cannonball have the same momentum (big mass, small velocity vs. small mass, big velocity). But since the momentum for each is moving in the opposite direction, the momentums cancel out, causing the cannon-cannonball system's momentum to equal zero.

Explanation:

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Why are computer simulations useful in studying phenomena in the universe?

kenny6666 [7]

Computer simulation is useful because it helps in the prediction of what will likely happen in the future using data from past events.

<h3>What is computer simulation?</h3>

This is the use of computer models to represents a hypothetical scenarios that are likely to be obtained in the real world.

Computer simulations are useful in studying phenomena in the universe because they help us to achieve the followings;

It helps in the prediction of what will likely happen in the future using data from past events.
It saves cost and time of carrying out actual experiments.
It can help prevent a disaster that may occur in the future.

Learn more about computer simulations here: brainly.com/question/22214039

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2 years ago

A scientist claimed that fabric A is better able to resist fire than fabric B. Which option describes an experiment that will pr

UNO [17]

Answer:

B. Hold each type of fabric over a candle flame and time how long it takes for the fabric to start to burn.

Explanation:

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4 years ago

MIDDLE SCHOOL SCIENCE<br> yee yee please answer 6, 7, and 8

Nikolay [14]

Answer:

what r the questions i can’t see them

Explanation:

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3 years ago

One litre of crude oil weighs 9.6N. Calculate its specific weight, density and specific gravity.

Zepler [3.9K]

Answer:

The answer is " $\bold{9600 \frac{N}{m^3}, 978.59 \frac{kg}{m^3}, and \ 0.978}$ "

Explanation:

Given:

$\to v=1\ liter= 10^{-3} \ m^3\\\\\to w= 9.6 \ N\\$

calculation:

$Specific \ weight =\frac{w}{v}=\frac{9.6}{10^{-3}}=9600 \frac{N}{m^3} \\\\w=mg\\\\m= \frac{w}{g}=\frac{9.6}{9.81}=0.9785\ kg\\\\\rho\ (density)=\frac{m}{v}=\frac{0.9785}{10^{-3}}=978.59 \frac{kg}{m^3}\\\\specific \ gravity = \frac{\prho \ obj}{\rho w}=\frac{978.54}{1000}=0.978$

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3 years ago

The pointer of an analog meter is connected to a

dangina [55]

C. coil suspended by bearings.
<span>but im not 100% sure</span>

8 0

3 years ago

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