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qwelly [4]
3 years ago
11

Glassy and metallic are terms that describe what mineral property? A.luster B.color C.shape D.hardness

Physics
2 answers:
lana66690 [7]3 years ago
6 0
The answer is A.luster
Otrada [13]3 years ago
5 0

The correct answer is option A. Luster

Hope this helps! :)

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I need SO much help please!!!!!!!!~!
bulgar [2K]
Hi,

I've found a link that should assist you or answer your question.
http://click.dji.com/ANbvbbP7bwUWtSACp6U_?pm=link&as=0004

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3 0
4 years ago
the density of dead sea surface water is about 1.166 g/ml. how much mass, in grams, would 2 liters of this salty water have?
kogti [31]
<span>Density is a value for mass, such as kg, divided by a value for volume, such as m^3. Density is a physical property of a substance that represents the mass of that substance per unit volume. The mass of the salty water is calculated as follows:

Mass = 1.166 g/mL ( 2000 mL ) = 2332 g of salty water</span>
6 0
3 years ago
Read 2 more answers
What are the two opposing forces that keep stars between collapsing and inflating?
boyakko [2]
The answer is pressure and gravity
5 0
3 years ago
The severity of a fall depends on your speed when you strike the ground. All factors but the acceleration from gravity being the
Diano4ka-milaya [45]

Answer:

<em>The object could fall from six times the original height and still be safe</em>

Explanation:

<u>Free Falling</u>

When an object is released from rest in free air (no friction), the motion is completely dependant on the acceleration of gravity g.

If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy of

U=m.g.h

When the object strikes the ground, all the mechanical energy (only potential energy) becomes into kinetic energy

\displaystyle K=\frac{1}{2}m.v^2

Where v is the speed just before hitting the ground

If we know the speed v is safe for the integrity of the object, then we can know the height it was dropped from

\displaystyle m.g.h=\frac{1}{2}m.v^2

Solving for h

\displaystyle h=\frac{m.v^2}{2mg}=\frac{v^2}{2g}

If the drop had occurred in the Moon, then

\displaystyle h_M=\frac{v_M^2}{2g_M}

Where hM, vM and gM are the corresponding parameters on the Moon. We know v is the safe hitting speed and the gravitational acceleration on the Moon is g_M=1/6 g

\displaystyle h_M=\frac{v^2}{2\frac{1}{6}g}

\displaystyle h_M=6\frac{v^2}{2g}=6h

This means the object could fall from six times the original height and still be safe

6 0
4 years ago
A disk between vertebrae in the spine is subjected to a shearing force of 425 N. Find its shear deformation, taking it to have a
zzz [600]

Answer:

option A

Explanation:

given,

shear force = 425 N

Shear modulus = 1.7 × 10⁹ N/m²

disk equivalent to solid cylinder

height = 0.7 cm  and diameter = 6.50 cm

\delta = \dfrac{VL}{AG}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi d^2\times 1.7\times 10^9}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi\times 0.065^2\times 1.7\times 10^9}\\\\\delta  = 5.27 \times 10^{-7} m

hence, the correct answer is option A

3 0
4 years ago
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