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cestrela7 [59]
3 years ago
13

The domain of rational function gis the same as the domain of rational function f. Both f and g have a single x-intercept at x =

-10. Which
equation could represent function g?
A. g(x) = 10px)
B. 8(x) = f(x + 10)
C. 8(x) = f(x) + 10
D. g(x) = f(x) - 10
Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0
The answer for this is D
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Step-by-step explanation:

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Combine Radicals/Fractional Exponents
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\mathsf{Given :\;\;\dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{64x^3y^3}}}

\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{4^3x^3y^3}}}

\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{(4xy)^3}}}

\bigstar\;\;\textsf{We know that : \boxed{\mathsf{\sqrt[n]{a} = a^{\dfrac{1}{n}}}}}

\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{(4xy)^{\dfrac{3}{3}}}}}

\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{4xy}}}

\mathsf{\implies \left(\dfrac{5}{4}\right) \left(\dfrac{x^{\dfrac{-3}{2}}}{{x}}\right)\left(\dfrac{y^{-2}}{y}\right)}

\bigstar\;\;\textsf{We know that : \boxed{\dfrac{a^m}{a^n} = a^{m - n}}}}

\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3}{2} - 1\right)}}y^{(-2 - 1)}}

\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3 - 2}{2}\right)}}y^{-3}}

\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-5}{2}\right)}}y^{-3}}

\textsf{Comparing the above with $\mathbf{ax^by^c}$, We can notice that :}

\bigstar\;\;\mathsf{a = \dfrac{5}{4}}

\bigstar\;\;\mathsf{b = \dfrac{-5}{2}}

\bigstar\;\;\mathsf{c = -3}

\implies \mathsf{Product\;of\;a,\;b\;and\;c = \left(\dfrac{5}{4}\times \dfrac{-5}{2} \times -3\right)}

\implies \mathsf{Product\;of\;a,\;b\;and\;c = \dfrac{75}{8}}

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4 years ago
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Likurg_2 [28]
4 hours. 
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7 0
4 years ago
Urgent help needed, thanks!
SSSSS [86.1K]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
-2x+11+6x help please ASAP
Virty [35]
-2x + 11 + 6x

put the x’s together
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put them together again
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bring 11 on other side with (-)
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divide by 4
x = -11/4

answer
x = -11/4 or -2.75
6 0
4 years ago
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