Since AM = 2cm and AC = 6cm we can write the following:
AM + AC = 8cm
So, now we only create a fraction demonstration the length from AM to AC:
which can be simplified to
Conclusion/answer:
The length from AM to AC is:
Hope it helped,
BioTeacher101
Answer:
Step-by-step explanation:
You have to use the discriminant for this. If the quadratic is , then
a = -4, b = -3, and c = 7. The formula for finding the discriminant is
which comes from the quadratic formula, but without the square root sign. Filling in:
which simplifies down to
D = 9 + 112 so
D = 121. This is a perfect square, so the solutions will be 2 real. Just so you know, you will NEVER have a solution like the one offered in the third choice down. If you have one imaginary root, you will ALWAYS have a second by the conjugate rule.
Answer:
6√3 ±3 ≈ {7.392, 13.392}
Step-by-step explanation:
The length of AB is the long side of a right triangle with hypotenuse CD and short side (AC -BD). The desired radius values will be half the length of EF, with AE added or subtracted.
__
<h3>length of AB</h3>Radii AC and BD are perpendicular to the points of tangency at A and B. They differ in length by AC -BD = 12 -9 = 3 units.
A right triangle can be drawn as in the attached figure, where it is shaded and labeled with vertices A, B, C. Its long leg (AB in the attachment) is the long leg of the right triangle with hypotenuse 21 and short leg 3. The length of that leg is found from the Pythagorean theorem to be ...
AB = √(21² -3²) = √432 = 12√3
<h3>tangent circle radii</h3>This is the same as the distance EF. Half this length, 6√3, is the distance from the midpoint of EF to E or F. The radii of the tangent circles to circles E and F will be (EF/2 ±3). Those values are ...
6√3 ±3 ≈ {7.392, 13.392}
