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alina1380 [7]
3 years ago
6

⚠️NEED HELP ASAP ⚠️ in the figure below ARE is similar to ADEF. Find the length of EF

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
6 0

Answer:

I think that the length of E and F is 6

Step-by-step explanation:

if you take 2x + 1

carry over the two on the 1 and adding it making it a 3

then it becomes x3 and x3 = to 6

so therefore I think your answer would be 6.

it is fuzzy so if it is wrong I am very sorry.

ycow [4]3 years ago
3 0

Answer:21

Step-by-step explanation:

4/7=x+2/2x+1

x=10

So,EF=10×2+1

=21

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34​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 student are sampled, so n = 10

34% of college students say they use credit cards because of the rewards program, so \pi = 0.34

(a) exactly​ two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157

P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573

P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320

P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0
3 years ago
Original price: $64; Markup: 15% what is the retail price?
Brrunno [24]

Answer:

$73.60

Step-by-step explanation:

Original price:  $64

Markup:  0.15($64) = $9.60

New retail price:  $64 + $9.60 = $73.60

4 0
3 years ago
Electric current flowing through wire produces heat that
morpeh [17]
I’m not sure? But don’t answer the guy with the bitly it’s a scam
5 0
3 years ago
Which of the following is the length of the<br> altitude a of the equilateral triangle below?
maria [59]

Answer:

A) \sqrt{3}

Step-by-step explanation:

in a 30-60-90 triangle the sides, respectively, are in the ratio of 1 : \sqrt{3} : 2

3 0
2 years ago
Suppose Q and R are independent events. Find P(Q and R). P(Q) = 0.87, P(R) = 0.51
eimsori [14]

Answer:

0.4437

Step-by-step explanation:

First we will define independent events.

Two events are said to be independent when the occurrence of one event doesn't affect the probability of occurrence of second event.

Given

P(Q)=0.87

and  

P(R)=0.51

The probability of independent events is given as:

P(Q∩R)=P(Q)*P(R)

=0.87*0.51

=0.4437

So the probability of Q and R is 0.4437 ..  

5 0
3 years ago
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