Answer:divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.
Step-by-step explanation:
divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.
<u>Answer:</u>
The correct answer options are C.
and D.
.
<u>Step-by-step explanation:</u>
The values which make the denominator equal to zero are called the excluded values.
Here, we can substitute 8 for x and check if it makes the denominator 0.





20x^2y - 4xy
First, we look at what terms are common between each term.
There is a 4 present in the last term, and 4 is a factor of 20, so that is one factor.
Each term also includes at least one x, and one y, so x and y are also factors.
We can factor a 4, an x, and a y out of this.
<h3><u>4xy(5x - 1) is the fully factored form of this binomial. </u></h3>