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sertanlavr [38]
3 years ago
9

Pls help me with this problem

Mathematics
2 answers:
Fed [463]3 years ago
8 0
You got it correct
1: greater than 1
2: less than -1
3: neither
4: greater than 1
5: less than -1
dmitriy555 [2]3 years ago
4 0

Answer: 5

Step-by-step explanation: x means 5

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Complete this question.
Naddik [55]

Answer:

The evidence from the story is base of the new church in this period and the first child to be a part in church and church of the church

Step-by-step explanation:

6 0
3 years ago
The point P= (x,-1/7) lies on the unit circle shown below. What is the value of x in simplest form? ​
ipn [44]

Answer:

x^2 + \frac{1}{49} =1

And solving for x we got:

x^2 = 1- \frac{1}{49}

x^2 = \frac{48}{49}

And taking square root we got:

x = \sqrt{\frac{48}{49}}= \frac{\sqrt{48}}{7} = \frac{4\sqrt{3}}{7}

Step-by-step explanation:

For this case we have the following point given P(x , -1/7)

And we want to find the value of x, since P lies on the unitray circle if we find the distance from P to the center of the unitary circle (0,0) we need to get 1. Using the definition of Euclidean distance that means:

d = \sqrt{(x -0)^2 +(-1/7 -0)^2}=1

And if we square both sides of the last equation we got:

x^2 + \frac{1}{49} =1

And solving for x we got:

x^2 = 1- \frac{1}{49}

x^2 = \frac{48}{49}

And taking square root we got:

x = \sqrt{\frac{48}{49}}= \frac{\sqrt{48}}{7} = \frac{4\sqrt{3}}{7}

3 0
3 years ago
each side of triangle xyz has length 9 .Find the area of the region inside the circumcircle of the triangle but outside the tria
mote1985 [20]

Answer:

The area of the region inside the circumcircle of the triangle but outside the triangle is

A=\frac{27}{4}[\pi-3\sqrt{3}]\ units^2

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the area of triangle

we have an equilateral triangle

Applying the law of sines

A_t=\frac{1}{2}(b^2)sin(60^o)

where b is the length side of the equilateral triangle

we have

b=9\ units

A_t=\frac{1}{2}(81)sin(60^o)

A_t=\frac{1}{2}(81)\frac{\sqrt{3}}{2}

A_t=81\frac{\sqrt{3}}{4}\ units^2

step 2

Find the area of circle

The area of the circle is equal to

A_c=\pi r^{2}

The formula to calculate the radius of the circumcircle of the triangle equilateral is equal to

r=b\frac{\sqrt{3}}{6}

where b is the length side of the equilateral triangle

we have

b=9\ units

substitute

r=(9)\frac{\sqrt{3}}{6}

r=3\frac{\sqrt{3}}{2}\ units

Find the area

A_c=\pi (3\frac{\sqrt{3}}{2})^{2}

A_c=\frac{27}{4} \pi\ units^2

step 3

Find the area of the shaded region

we know that

The area of the region inside the circumcircle of the triangle but outside the triangle is equal to the area pf the circle minus the area of triangle

so

A=(\frac{27}{4} \pi-81\frac{\sqrt{3}}{4})\ units^2

Simplify

A=\frac{27}{4}[\pi-3\sqrt{3}]\ units^2

6 0
3 years ago
The Big Men retailer reduced the price of its $350.00 sport coats by 30%. Calculate the new price?
egoroff_w [7]
New price would be $245.
5 0
3 years ago
Read 2 more answers
Susan tossed a die 996 times. which of the following would be a good estimate of the number of times she got the number 3 on the
nignag [31]

Answer:

i believe the answer is 332

Step-by-step explanation:

basically what i did was divide 3 and 996. when you do that it will let you know the estimate number of the number times she  got number 3 on the die.

5 0
3 years ago
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