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natita [175]
2 years ago
15

Help asap pls! A fish tank is shaped like a rectangular prism.

Mathematics
1 answer:
Serggg [28]2 years ago
3 0

Answer:

A. Makes the most sense. If you are using multiplication you'd get 18 1/16

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The old man looked out, then beckoned frantically for Greg to follow him. For a moment Greg couldn’t move. Then he found himself
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i think its A?

Step-by-step explanation:

because he is warning greg?

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In an hour a jogger burns about 4 calories per pound of body weight. How many calories will a jogger burn who weighs 151 pounds
harina [27]
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The jogger will burn 604 calories after an hour of jogging.
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Solve the following inequality: -20 < 4- 2x
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54:63 in simplest form
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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
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