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Lerok [7]
3 years ago
6

What is (4 - 5y) - 2 (3.5y - 8)

Mathematics
2 answers:
swat323 years ago
8 0

Answer:

It's 20 - 12<em>y</em>

Step-by-step explanation:

I sorta just worked it out, I dunno how..

kondaur [170]3 years ago
3 0

Answer:

20-12y

Step-by-step explanation:

The answer is simple

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A random variable Y is such that E(y)= 3.8 and Var(y)= 2.16<br> Calculate E( 3y +2) <br> Var( 3y+ 2)
Naya [18.7K]

The expectation, E(3y +2) and variance, Var(3y+2) of the random variable are 13.4 and 19.44 respectively

<h3>How to determine the expectation and variance of a random variable?</h3>

The expectations or expected value E(y) of a random variable can be thought of as the “average” value of the random variable. It is also called its mean

By definition:

if y = ax + b

then E(y) = aE(x) + b

where a,b = constant

The variance V(y) of  a random variable is the measure of spread for the distribution of a random variable that determines the degree to which the values of a random variable differ from the expected value

By definition

if y = ax + b

V(b) = 0

V(y) = V(ax) + V(b)

      = a²V(x) + 0

where a,b = constant

Given: E(y)= 3.8 and Var(y)= 2.16

Calculate E( 3y +2) and Var( 3y+ 2)

E(3y +2) = 3E(y) + 2            since E(y) = 3.8

           = 3×3.8 + 2

          = 11.4+2

          = 13.4

Var(3y+2) =  3²Var(y) + 0

               = 9×2.16

               = 19.44

Therefore, E(3y +2) is 13.4 and Var(3y+2) is 19.44

Learn more about expectations and variance on:

brainly.com/question/15858152

#SPJ1

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