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OLEGan [10]
3 years ago
14

Drag the tiles to the correct boxes to complete the pairs.

Chemistry
2 answers:
lukranit [14]3 years ago
8 0
That so so hard man
svlad2 [7]3 years ago
5 0

Answer:

I think the answer is in the picture

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Which statement below about contrasting Hb and Mb is FALSE?
olchik [2.2K]

Answer:

C. Hb binds O2 more tightly than Mb.

Explanation:

<u>Hb and Mb are both oxygen carrier protiens which contain the heme group. Hb has 4 heme units in 1 moleucle which work via coperative effect. On the other hand, Mb has only one heme unit. </u>

<u>From above theory, statement A and B are correct.</u>

<u>Although the heme group of the Mb is identical to those of Hb, Mb has a higher affinity for carrying oxygen than hemoglobin.</u>

<u>Hence, Statement C is wrong.</u>

Thats why the function of hemoglobin is to transport oxygen and that of myoglobin is to store oxygen.

<u>When a curve is plotted between oxygen accepted and the pressure of the oxygen, Hb shows sigmoidal, whereas Mb shows hyperbolic oxygen saturation curves.</u><u> The statement D is correct.</u>

<u>Bohr effect and various factors decribe the statement : Hb-oxygen binding is dependent on physiological changes in pH, whereas Mb-oxygen binding is not. </u><u>The  statement E is also correct.</u>

7 0
2 years ago
5.58e-18 + 8.65e-13 / -8.76e+06
evablogger [386]

Answer:

this is the answer:

− 10.13099839

Explanation:

5 0
3 years ago
I need help with B and C
lakkis [162]
B) Mg is the alkaline earth metal w/12 protons so following the periodic table to the halogen in the same period is

Cl: Chlorine

C) The Neutral noble has w/ 18 electrons is argon so the metal in the same row is

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8 0
3 years ago
The coordination number of cation and anion in fluorite CaF2 and antifluorite Na2O are respectively​
sp2606 [1]

<u>8:4 and 4:8</u> both have CCP structure............................... ᐛ

6 0
3 years ago
A sample of gas in a cylinder as in the example in Part A has an initial volume of 48.0 L , and you have determined that it cont
masya89 [10]

Answer:

0.45 moles

Explanation:

The computation of the number of moles left in the cylinder is shown below:

As we know that

\frac{n1}{V1} = \frac{n2}{V2}

we can say that

n2 = n1 \times \frac{V2}{V1}

where,

n1 = 1.80 moles of gas

V2 = 12.0 L

And, the V1 = 48.0 L

Now placing these values to the above formula

So, the moles of gas in n2 left is

= 1.80 \times \frac{12.0\ L}{48.0\ L}

= 0.45 moles

We simply applied the above formulas so that the n2 moles of gas could arrive

5 0
3 years ago
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