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Alja [10]
3 years ago
12

Which of the following factors drives all the weather on Earth, including large-scale storms and local weather systems? The ocea

n holds thermal energy more efficiently than land. The greenhouse effect ensures that some thermal energy will always be trapped near the Earth's surface. The Sun heats up the air at different rates, and the atmosphere undergoes changes to equalize temperatures and pressures. The Coriolis effect curves the motion of wind due to the Earth's rotation.
Chemistry
2 answers:
katovenus [111]3 years ago
5 0
The sun heats up the air at different rates. Weather is caused by uneven heating
Serhud [2]3 years ago
5 0

Answer: The Sun heats up the air at different rates, and the atmosphere undergoes changes to equalize temperatures and pressures.

Explanation: The Sun's unequal heating of the air is the driving force behind all weather systems on Earth. As the atmosphere undergoes changes to equalize temperature and pressure, fronts and storms are created.

Hope this helps you.

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How many grams are there in 7.4 x 1023 molecules of H2SO4?
bazaltina [42]

7.4x10^23 = molecules of silver nitrate sample  

6.022x10^23 number of molecules per mole (Avogadro's number)  

Divide molecules of AgNO3 by # of molecules per mol  

7.4/6.022 = 1.229 mols AgNO3 (Sig Figs would put this at 1.3)  

(I leave off the x10^23 because they both will divide out)  

Use your periodic table to find the molar weight of silver nitrate.  

107.868(Ag) + 14(N) + 3(16[O]) = 169.868g/mol AgNO3  

Now multiply your moles of AgNO3 with your molar weight of AgNO3  

1.229mol x 169.868g/mol = 208.767g AgNO3

4 0
4 years ago
The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond
balu736 [363]
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is 
     C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is 
     6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation 
     ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
     ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
     ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
                           = -1273.3 - (0 + 0 + 0)
                           = -1273.3
8 0
3 years ago
hydrogen combines with sulfur much like hydrogen combines with oxygen draw an electron dot diagram showing hydrogen combined wit
sertanlavr [38]

hydrogen combines with sulfur is H2S

<span> hydrogen combines with oxygen H2O</span> <span>Hydrogen sulfide<span> <span>is the </span></span>chemical compound<span> <span>with the </span></span>formula <span>H<span>
2S</span></span>. It is a colorless gas<span> <span>with the characteristic foul odor of rotten </span></span>eggs<span>; it is heavier than air, very poisonous, corrosive, flammable, and explosive; properties shared with the denser </span>hydrogen chalcogenides</span>

<span> </span>

6 0
3 years ago
What mass of natural gas (ch4) must you burn to emit 272 kj of heat?
balandron [24]
CH4 + 2 O2 ---> CO2 + 2 H2O Q = 891,6 kJ / mol CH4

1 mol CH4 = 16 g

16 g ---- 891,6 kJ
x g ----- 272 kJ

x = 272 kJ × 16 g / 891,6 kJ = 4,88 g

You must burn 4,88 g of CH4.

:-) ;-)
7 0
3 years ago
Paul has different spoons for cooking. He told Sue that he likes to stir hot food with a wooden spoon because it does not burn h
IceJOKER [234]

Answer:

Sue was not right as wood is not a heat conductor and will not allow heat to pass through the spoon thus keeping the hand safe. In a meatal spoon, heat can pass through and burn the hand as meatal is a good conductor of heat.

8 0
3 years ago
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