The area of a sector of a circles is calculated by the equation A = πr^2 (theta/360). From the data of the sector, we determine the radius of the circle. THen, we can calculate for the area of the circle.
16.4π = πr^2 (72/360)
r = 9.06
Area of circle = πr^2
Area of circle = π(9.06)^2
Area of circle = 82π
This is your perfect answer
First, let's convert each line to slope-intercept form to better see the slopes.
Isolate the y variable for each equation.
2x + 6y = -12
Subtract 2x from both sides.
6y = -12 - 2x
Divide both sides by 6.
y = -2 - 1/3x
Rearrange.
y = -1/3x - 2
Line b:
2y = 3x - 10
Divide both sides by 2.
y = 1.5x - 5
Line c:
3x - 2y = -4
Add 2y to both sides.
3x = -4 + 2y
Add 4 to both sides.
2y = 3x + 4
Divide both sides by 2.
y = 1.5x + 2
Now, let's compare our new equations:
Line a: y = -1/3x - 2
Line b: y = 1.5x - 5
Line c: y = 1.5x + 2
Now, the rule for parallel and perpendicular lines is as follows:
For two lines to be parallel, they must have equal slopes.
For two lines to be perpendicular, one must have the negative reciprocal of the other.
In this case, line b and c are parallel, and they have the same slope, but different y-intercepts.
However, none of the lines are perpendicular, as -1/3x is not the negative reciprocal of 1.5x, or 3/2x.
<h3><u>B and C are parallel, no perpendicular lines.</u></h3>
Answer:
y = 1
Step-by-step explanation:
Slope is written in the form y=mx+b. Where m is the slope and b is the y-intercept.
When there isn't a slope, as in the line is flat and it isn't moving up or down, you wouldn't write anything for it. You would just write y equals the y-intercept (y = b).
Likewise, if the y-intercept is at (0,0), then you'd only write y equals the slope (y = mx).
Hopefully this makes sense :)
Btw, I also answered in the main comments earlier, so you can check that out as well.
The roots of a quadratic equation<span> are the </span>x-intercepts<span> of the </span>graph<span>. ... A </span>quadratic equation<span> has </span>two<span>roots if its </span>graph<span> has </span>two x-intercepts<span>; A </span>quadratic equation<span> has ... Here you can get a visual of your</span>quadratic function<span> ...</span>
