Answer:
N₂
Explanation:
Sodium is a larger molecule with a much higher molecular weight. However, 20g of N₂ would be a smaller amount of molecules than 20g of sodium due to how there are multiple nitrogen molecules.
2/3 * given mass of N₂ = mass of N₃
N₃ (Azide ion) given mass = 20g
Na = 20g
Masses of chemicals are equal
Na = 22.990g/mol
20g/22.990g/mol = 0.8699mol of Na
N₃ = 20g
N₃ = N g/mol x 3
N = 14.007 g/mol
14.007 x 3 = 42.021 g/mol
N₃ = 42.021g/mol
20g/42.021g/mol = 0.4759 mol of N₃
Notice how there are fewer moles of the Azide ion than the Sodium.
0.4759 moles of NaN₃ is produced
combine molecular weights:
42.021 + 22.990 = 65.011 g/mol
multiply by amount of moles of the limiting reactant:
0.4759 mol *65.011 = 30.942 g
Also, here is the balanced equation:
3N₂ + 2Na = 2NaN₃
The results are the same as the balanced equation.
