In a refrigerator/freezer combo, the probability that both the refrigerator and freezer will fail is

1 answer:

5 0

Ok bet jdhdhrhhdhdhfhhfhfhfhhfhhfhdhdhjfhfhfhfhfhjfjfhhfhfhfhfhjfhfhjfhfjfjfbdvbdbdhdh gg fhhdhdhdhdhfhfhfhfhfhfhffhhfhfhfhfhfhfhfhhfhfhfhjfjfhfhfhfhfhhfhfhfhfhfhhfhfhfjghfjfhfjfhfjgjjgjgjgjgjgjjgjgjgjgjjgjgjgjgjgjhfhjfh

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Ben ran 3/4 km in a race . Jane ran2/9 of the distance that Ben had run . What was the distance that Jane ran? Help pls! Thanks

horsena [70]

'of' means mltilply
jane=2/9 of ben
ben=3/4
jane=2/9 of 3/4
jane=2/9 times 3/4=(2*3)/(9*4)=6/36=1/6 miles

8 0

3 years ago

The quotient of a number and 3 is 6

KengaRu [80]

Step-by-step explanation:

the quotient of a number and 3 is 6

Solution,

Let the number be x, then

$\frac{x}{3} = 6 \\ x = 6 \times 3 \\ x = 18$

5 0

3 years ago

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A golden rectangle is a rectangle whose length is approximately 1.6 times its width.the early greeks thought that a rectangle wi

Scrat [10]

Mike has 78 feet of fencing available for his garden, this is the perimeter (P) of the rectangle:
Perimeter: P=78 feet

The formula of Perimeter is:
P=2(W+L), where W is the width and L is the length, then:

P=78→2(W+L)=78
Dividing both sides of the equation by 2:
2(W+L)/2=78/2
W+L=39

If the shape is of a golden rectangle, we know:
L=1.6W
Replacing this above:
W+1.6W=39
Adding similar terms:
2.6W=39
Solving for W
2.6W/2.6=39/2.6
W=15 feet

L=1.6W=1.6(15)→L=24 feet

Answer: T<span>he dimensions of the garden are: Width=15 feet and Length=24 feet. </span>

4 0

3 years ago

Biruk wants to buy a book for $15.25 and a book for $4.85. He wants to pay with one $20 bill. Use estimation to decide if this i

ycow [4]

First round 15.25 to 15.30 and round 4.85 to 4.90 and then add you get 21.20 no it is not reasonable and you round to the decimal ones

8 0

4 years ago

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<img src="https://tex.z-dn.net/?f=%20%5Cint%20%5Cfrac%7Bdx%7D%7Bxln%5E%7Bp%7Dx%20%7D" id="TexFormula1" title=" \int \frac{dx}{xl

Eva8 [605]

Substitute $u=\ln x$ , so that $\mathrm du=\dfrac{\mathrm dx}x$ . The integral is then equivalent to

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\int\frac{\mathrm du}{u^p}=\begin{cases}\dfrac{u^{p+1}}{p+1}+C&\text{for }p\neq1\\\\\ln|u|+C&\text{for }p=1\end{cases}$

Then transforming back to $x$ gives

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\begin{cases}\dfrac{\ln^{p+1}x}{p+1}+C&\text{for }p\neq1\\\\\ln|\ln x|+C&\text{for }p=1\end{cases}$

4 0

3 years ago