CX is an altitude in triangle ABC. Which statements are true? Select two options. .

Mathematics

1 answer:

Nastasia [14]3 years ago

5 0

Answer:

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Plz help me with it !

Kipish [7]

Answer: $\bold{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt{2}}$

<u>Step-by-step explanation:</u>

$\dfrac{\sqrt7-5}{\sqrt7+\sqrt8}\bigg(\dfrac{\sqrt7-\sqrt8}{\sqrt7-\sqrt8}\bigg)=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{7-8}=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{-1}\\\\\\=\boxed{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt2}$

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3 years ago

Init. Cantian Sinaniiieeintroduction

tatuchka [14]

Answer:

The independent variable is the amount of miles walked, and the dependent is the total from home.

Step-by-step explanation:

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3 years ago

If angle 4 is 52.7, what are the measures of angles 1,2, and 3?

shusha [124]

Answer:

127.3
52.7
127.3
52.7

Step-by-step explanation:

Since we know the angle measure of angle 4, we already know that angle 2 will have the same measure according to do the vertical angle theorem. Now to find angles 1 and 3, we can make an equation and solve for x (supplementary angles).

52.7 + x = 180

x = 127.3

Best of Luck!

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4 years ago

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Sigma notation from sum. pls help?? sorry for the calc spam :P

givi [52]

To the risk of sounding redundant,

$\bf \begin{array}{ccccccccc}
k=2&&k=3&&k=4&&k=5&&k=6\\\\
\frac{\underline{2}+2}{2(\underline{2})}&&\frac{\underline{3}+2}{2(\underline{3})}&&\frac{\underline{4}+2}{2(\underline{4})}&&\frac{\underline{5}+2}{2(\underline{5})}&&\frac{\underline{6}+2}{2(\underline{6})}\\\\
1&+&\cfrac{5}{6}&+&\cfrac{6}{8}&+&\cfrac{7}{10}&+&\cfrac{8}{12}
\end{array}$

and surely you'd know what that is.

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3 years ago