Answer:
155.3 m
Step-by-step explanation:
<u>We have:</u>
θ: is the angle measured from the vertical = 75 °
v = is the speed of the submarine = 10 m/s
t = 1 min
The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:
<u>Where:</u>
d: is the distance traveled by the submarine in 1 minute
x: is the deep to find
The distance, d, is:
Now, the deep is:
Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.
I hope it helps you!
Answer:
y = 5x - 7
Step-by-step explanation:
Using the equation of a line with two points
y_2 - y_1 / x_2 - x_1 = y - y_1 / x - x_1
Giving two points
( -4 , 10)(16 , -2)
x_1 = -4
y_1 = 10
x_2 = 16
y_2 = -2
Using the above formula
y_2 - y_1 / x_2 - x_1 = y - y_1 / x - x_1
-12 - 3 / -1 - 2 = y - 3 / x - 2
-15/-3 = y - 3 /x - 2
Cross multiply
-15(x - 2) = -3(y - 3)
-15x + 30 = -3y + 9
-15x + 30 + 3y - 9 = 0
-15x +30 - 9 + 3y = 0
-15x + 21 + 3y = 0
3y = 15x - 21 ( following y = mx + C
Dividing through by 3 to find y
3y/3 = 15x -21 / 3
y = 15x - 21 / 3
We can still separate
y = 15x / 3 - 21/3
y = 5x - 7
Therefore, the equation of the line is
y = 5x - 7
Answer: 20
Step-by-step explanation:
Answer: p= -3/13
Step-by-step explanation:
-10+26p=-16
+10 +10
26p =-6
26 26
p= -3/13
Answer:
c and b
Step-by-step explanation:
