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Strike441 [17]
3 years ago
9

A dry beaker has a mass of 55.0 g. When 50.0 mL of water is added to the beaker, the mass of the water and the beaker is 105.0 g

. What is the density of the water?
Biology
1 answer:
Artemon [7]3 years ago
6 0
The answer is 2.1 g/ml

D = M/V

105.5/50.0 = 2.1
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Part C
IrinaVladis [17]

Answer:

                     (i) 1 moles of C

                     (ii) 4.5 moles of C

Explanation:

                   The Chemical equation is as follow,

                                             A + 2 B  →  C

This chemical equation can be translated as;

(i) 1 mole of A reacts with 2 moles of B

(ii) 1 mole of A produces 1 mole of C

(iii) 2 moles of B reacts with 1 mole of A

(iv) 2 moles of B produces 1 mole of C

(v) 1 mole of C is produced by 1 mole of A and 2 moles of B

Therefore to find the number of moles of C produced by 2 mole of B we will do following proportional method.

As,

                        2 moles of B produced  =  1 mole of C

So,

                    2 moles of B will produce  =  X moles of C

Solving for X,

                      X =  2 moles × 1 mole / 2 moles

                      X =  1 moles of C

Note:

         In above problem the given moles were the same as that present in balance equation so incase if the moles are different from that of the equation then the method shown above can be used to solve it.

Lets try it for 9 moles of B:

As,

                        2 moles of B produced  =  1 mole of C

So,

                    9 moles of B will produce  =  X moles of C

Solving for X,

                      X =  9 moles × 1 mole / 2 moles

                      X =  4.5 moles of C

5 0
3 years ago
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