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2 years ago

If you know the rest of the answers pls help me

Mathematics

1 answer:

netineya [11]2 years ago

3 0

Answer:

.45 times 6= 2.7

29 times 8 =232

.62 times 19 = 11.78

8.7 times 12=104.4

11.9 times 4 = 47.6

Step-by-step explanation:

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An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

2 years ago

Listed below are amounts (in millions of dollars) collected from parking meters by a security service company and other compan

dezoksy [38]

Given: Security Service Company:
1.4 1.8 1.6 1.7 1.5 1.5 1.7 1.6 1.5 1.6
Mean: 1.59
Standard Deviation: 0.014333

Other companies: 1.8 1.9 1.6 1.7 1.6 1.8 1.7 1.5 1.8 1.7
Mean: 1.71
Standard deviation: 0.014333

The coefficient of variation for security Service Company:

CV = (Standard Deviation/Mean) * 100.

= (0.14333/1.59) * 100

= 9.01%

The coefficient of variation for other companies:

CV = (Standard Deviation/Mean) * 100.

= (0.014333 / 1.71) * 100

= 8.38%

the limited data listed here show evidence of stealing by the security service company's employees because there is a significant difference in the variation.

6 0

4 years ago

Initial Knowledge Check

Anna [14]

Answer:

becos i know UwU

5 0

3 years ago

What is 4/20 + 6/10 =

Serhud [2]

Answer:

4/5