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3 years ago

Calculate the slope of the formed line using the following points: (-10.5) (0, -10).

Mathematics

1 answer:

grandymaker [24]3 years ago

6 0

The correct answer
-3/2
Explanation
You do (-10 - 5) / (0 - -10) or (x1 - y1) / (x2 - y2)

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PLZ HELP WUICK ILL MARK BRAINLEIST!!!

Otrada [13]

Answer:

3x - 20 = 5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A class survey found that 29 students watched television on Monday, 24 on Tuesday, and 25 on Wednesday. Of those who watched TV

gizmo_the_mogwai [7]

Answer:

There were 49 students in the class

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that watched TV on Monday

-The set B represents the student that watched TV on Tuesday.

-The set C represents the students that watched TV on Wednesday.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a is the number of students that only watched TV on Monday, $A \cap B$ is the number of adults that watched TV both on Monday and Tuesday, $A \cap C$ is the number of students that watched TV both on Monday and Wednesday, and $A \cap B \cap C$ is the number of students that watched TV on every day.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following subsets:

$a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)$

The sums of all of this values is the number of student that were there in the class. This means that we want to find the value of T:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = T$

We start finding the values from the intersection of three sets.

Solution:

12 students watched TV on all three days:

$A \cap B \cap C = 12$

14 students watched TV on both Monday and Tuesday

$A \cap B + A \cap B \cap C = 14$

$A \cap B = 14 - 12$

$A \cap B = 2$

Of those who watched TV on only one of these days, 13 choose Monday, 9 chose Tuesday, and 10 chose Wednesday.

$a = 13, b = 9, c = 10$

29 students watched television on Monday:

$A = 29$

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

$29 = 13 + 2 + (A \cap C) + 12$

$A \cap C = 29 - 27$

$A \cap C = 2$

24 on Tuesday

$B = 24$

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$24 = 9 + (B \cap C) + 2 + 12$

$B \cap C = 24 - 23$

$B \cap C = 1$

Now we have every value needed to find T:

$T = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$T = 13 + 9 + 10 + 2 + 2 + 1 + 12$

$T = 49$

There were 49 students in the class

7 0

4 years ago

In a school of 450 people 110 are in the choir 240 are in a band and 60 are in both

zhannawk [14.2K]

<em>The question doesn't require any specific probabilities, but I'm adding my own calculations to make it easier for you to solve your own problem</em>

Answer:

<em>Questions added and answered below</em>

Step-by-step explanation:

<u>Venn Diagram </u>

When we have different sets, some of them belong only to one set, some belong to more than one, some don't belong to any of them. This situation can be graphically represented by the Venn Diagrams.

Let's analyze the data presented in the problem and fill up the numbers into our Venn Diagram. First, we must use the most relevant data: there are 60 people in both the choir and the band. This number must be in the common space between both sets in the diagram (center zone, purple).

We know there are 110 people in the choir, 60 of which were already placed in the intersection zone, so we must place 110-60=50 people into the blue zone, belonging to C but not to B.

We are also told that 240 people are in a band, 60 of which were already placed in the intersection zone, so we must place 240-60=180 people into the red zone, belonging to B but not to C.

Finally, we add the elements in all three zones to get all the people who are in the choir or in the band, and we get 50+60+180=290. Since we have 450 people in the school, there are 450-290=160 people who are not in the choir nor in the band.

The question doesn't ask for a particular probability, so I'm filling up that gap with some interesting probability calculations like

a) What is the probability of selecting at random one person who is in the band but not in the choir?

The answer is calculated as

$\displaystyle P(A)=\frac{180}{450}=0.4$

b) What is the probability of randomly selecting one person who belongs only to one group?

We look for people who are in only one of the sets, they are 50+180=230 people, so the probability is

$\displaystyle P(B)=\frac{230}{450}=0.51$

b) What is the probability of selecting at random one person who doesn't belong to the choir?

We must add the number of people outside of the set C, that is 180+160=340

$\displaystyle P(C)=\frac{340}{450}=0.76$

7 0

3 years ago

?/5 =8/10 type the missing number that makes this fraction equal

SOVA2 [1]

<h2>- - - - - - - - - - - - - - - - - - </h2><h3> $\frac{?}{5} = \frac{8}{10}$ </h3><h3>Let's take the missing number as x.</h3>

<h3> $\frac{x}{5} = \frac{8}{10}$ </h3><h3>Means = Extremes </h3><h3> $x \times 10 = 5 \times 8$ </h3><h3> $x = \frac{5 \times 8}{10}$ </h3><h2>___</h2><h3>(Cancel by 2 table)</h3><h3> $x = \frac{5 \times4 }{5}$ </h3><h2>___</h2><h3>(Cancel by 5 table, So that we cancel 5 in the denominator and numerator)</h3><h3> $x = 4$ </h3><h2>- - - - - - - - - - - - - - - - - -</h2>

<h2>Therefore, The missing number is 4. </h2>

5 0

2 years ago

Read 2 more answers

The price of a watch is decreased by 10% to 3600. what will be it's original price?

LekaFEV [45]

Answer:

3960

Step-by-step explanation:

10% of 3600 = 360

3600 + 360 = 3960

5 0

4 years ago