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Assoli18 [71]
3 years ago
10

Help I don’t understand this

Mathematics
1 answer:
Ganezh [65]3 years ago
5 0

Answer:

Step-by-step explanation:

they are opposite angles, so we put them equal to each other.

25.

6a+10= 130

6a=120    a=20   so now we plug it in 6(20) +10= 130

26.   4a-4=2a+30

      2a=34      a=17   sso now we plug in 4(17)-4= 64    2(17)+30= 64

27.    6y+1=4y+9                             2x-5=x+7

          2y=8                                      x=2

         y=4

now plug in 6(4)+1=25     4(4)+9=25     2(2)-5= -1     (2)+7=9

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After graphing the lines, you can see that the solution is (4, -1)

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Make a line plot for each set of data.
Gala2k [10]

Answer:

Look at Step by Step

Step-by-step explaination

All you need to do is find the frequency of the test scores.

70 = 2 dots

75 = 0

80 = 3 dots because there are 3 students that got a 80 %

85 = 3 dots because there are 3 students that got a 80 %

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Find the value of the variable plz help
Naddika [18.5K]

Answer:

Step-by-step explanation:

Vertically opposite angles are equal.

8y + 36 = 14y -24                Subtract 36 to both sides

8y = 14y - 24 - 36               Combine

8y = 14y - 60                       Subtract 14y from both sides

8y - 14y = - 60

-6y = -60                             Divide by - 6

-6y/-6 = -60/-6

y = 10

===========================

x +48 = 64                        Subtract 48 from both sides

x +48 - 48 = 64-16

x = 16

                   

7 0
2 years ago
Read 2 more answers
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
Assume that the function f is a one-to-one function, (a) f(8) = 9, find f ^ -1 (9)
Annette [7]

(a) since we are given that f(8) = 9, the inverse of 9 is simply 8. Therefore, f^-1(9) = 8.

(b) Again, f is the inverse of f^-1, therefore, you simply switch numbers, and you get that f(-3) = -7.

8 0
3 years ago
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