Help I don’t understand this
1 answer:
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Complete question:
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
what is the area of the sector?
Answer:
The area of the sector = square units
Step-by-step explanation:
To find the area of the sector of a circle, let's use the formula:
Where, A = area
r = radius = 3
Substituting values in the formula, we have:
The area of the sector = square units
You need to know the properties of each function.
Tan is opposite (y) over adjacent (x). Sin>0 means that sin is positive, therefore, it is located on either quadrant 1 or 2. Tan=4/3 so it is located in quadrant 1.
The side of the triangle must be Adjacent=3 opposite=4 and hypotenuse=5
Now, you are asked to find the half angle of Cos which is
By following the formula, cos=3/5 then:
Multiply everything (inside the square 
root) by 5
Then just simplify
The answer is Square root of 20 over 5
Tan is opposite (y) over adjacent (x). Sin>0 means that sin is positive, therefore, it is located on either quadrant 1 or 2. Tan=4/3 so it is located in quadrant 1.
The side of the triangle must be Adjacent=3 opposite=4 and hypotenuse=5
Now, you are asked to find the half angle of Cos which is
By following the formula, cos=3/5 then: