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Minchanka [31]
2 years ago
10

Risks for standing up for the one who is being bullied

Computers and Technology
1 answer:
Afina-wow [57]2 years ago
3 0
You, in turn, might end up getting hurt or bullied.
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Which graphics format works best for desktop publishing and print work? (1 point) .tiff .gif .tga .jpeg?
Sergeeva-Olga [200]
. jpeg, probably works best
6 0
2 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
A constructor is just a special type of ______________ that instantiates an object from the class.
Dmitry_Shevchenko [17]

A constructor exists just a special type of subroutine that instantiates an object from the class.

<h3>What  is constructor?</h3>

A constructor exists as a special kind of subroutine in a class. It maintains the same name as the name of the class, and it has no return type, not even void. A constructor exists called with the new operator in order to create a new object.

A constructor exists as a special process of a class or structure in object-oriented programming that initializes a newly constructed object of that type. Whenever an object exists created, the constructor is called automatically. A constructor in Java exists as a special method that is utilized to initialize objects. The constructor exists called when an object of a class is created.

A subroutine exists as a sequence of program instructions that serves a specific task, packaged as a unit. This unit can then be utilized in programs wherever that separate task should be performed.

Hence,  A constructor exists just a special type of subroutine that instantiates an object from the class.

To learn more about constructor refer to:

brainly.com/question/13267121

#SPJ4

8 0
1 year ago
You manage a server that users store their document files on. you are finding that some users are utilizing more space than they
STALIN [3.7K]
You can set soft or hard quotas on file shares per user or per group. This would limit how much space a user can take up.
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3 years ago
Which reports indicate how traffic arrived at a website?.
tatyana61 [14]

Answer:

Direct traffics.

Explanation:

This channel refers to those traffics that came directly and without any via.

8 0
1 year ago
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