Answer:
#include <stdio.h>
void interchangeCase(char phrase[],char c){
for(int i=0;phrase[i]!='\0';i++){
if(phrase[i]==c){
if(phrase[i]>='A' && phrase[i]<='Z')
phrase[i]+=32;
else
phrase[i]-=32;
}
}
}
int main(){
char c1[]="Eevee";
interchangeCase(c1,'e');
printf("%s\n",c1);
char c2[]="Eevee";
interchangeCase(c2,'E');
printf("%s\n",c2);
}
Explanation:
- Create a function called interchangeCase that takes the phrase and c as parameters.
- Run a for loop that runs until the end of phrase and check whether the selected character is found or not using an if statement.
- If the character is upper-case alphabet, change it to lower-case alphabet and otherwise do the vice versa.
- Inside the main function, test the program and display the results.
The Lucent connector(LC) is a type of fiber optic connector used here.
Explanation:
A Lucent connector (LC) is a type of fiber optic connector connects to a terminating device by pushing the connector into the terminating device and can be removed by depressing the tab on the connector and pulling it out of the terminating device.
It is a standard ceramic Ferrule connector and has good performance and is favored for single mode.
LC is a latched connector which have same handling capacities like SC. They have small flange on top similar to an RJ-45 connector that aids secure connection. It has a smaller connector housing and a smaller 1.25 mm ferrule.
Answer:
import java.util.Scanner;
public class TestClock {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter two integer numbers");
int num1 = in.nextInt();
int num2 = in.nextInt();
int newSum=num1+10;
System.out.println("The first number is "+num1);
do{
System.out.println(newSum);
newSum +=10;
}while (newSum <=num2);
}
}
Explanation:
Using Java Programming language
- Prompt user for the two inputs and save them as num1 and num2(Using the scanner class)
- Create a new Variable newSum = num1+10
- Create a do...while loop to continually print the value of newSum, and increment it by 10 while it is less or equal to num2
