print("——OR——") Input ("Temperature value in degree Celsius:"), celsius 2 = float) Celsius 2 = (Fahrenheit 2 * 9/5) + 32; print the result.
The user's input is taken. Enter the temperature in celsius by typing it into the input box. Fahrenheit is equivalent to (celsius multiplied by 1.8) + 32 print(str(celsius)+ "A degree in Celsius is equal to a " + str(fahrenheit)+ " degree in Fahrenheit. The change from C to F is therefore 100/180, or 5/9. It is 180/100 or 9/5 from F to C. As a result, the conversion yields °F = °C (9/5) + 32. As a result, the equation for changing from the Celsius to Fahrenheit scale becomes °F = °C (9/5) + 32. To convert from degrees Fahrenheit to degrees Celsius, do the inverse calculation: subtract 30 from the degrees Fahrenheit reading, then multiply the result by two to obtain the degrees Celsius reading.
Learn more about conversion here-
brainly.com/question/13163755
#SPJ4
Answer:
Radio Corporation of America (RCA)
Explanation:
A corporation is not a video connector.
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
Answer:
A,C,D,E are the answers at least on the test i took
Explanation:
The number of bullet points on a slide should not exceed till 8
