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NISA [10]
3 years ago
10

2(x−4)+3x=7 solve for x

Mathematics
2 answers:
anyanavicka [17]3 years ago
8 0

Answer:

x = 3

Step-by-step explanation:

mk so here's a story I literally wrote down an ENTIRE on how to solve this problem and the stupid thing got deleted sooo ur on ur own kid HOWEVER am 100% positive this is the correct answer so <em>enjoy </em>:)

(btw try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations)    

sesenic [268]3 years ago
7 0

Answer:

x = 3

Step-by-step explanation:

5x - 8 + 8 = 7 + 8

5x = 15

5x/5 = 15/5

15 divided by 5 equals 3

Hope this helped you out :)

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69 + 12 can be rewritten as 3 (_*_)
Paladinen [302]

Take out the factor of 3 from both numbers

(69)/3 = 23

(12)/3 = 4

69 + 12 can be rewritten as 3(23 + 4)

~

8 0
3 years ago
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PLEASE PLEASE HELP the question is below
fiasKO [112]

Answer:

24

Step-by-step explanation:

First do parenthesis:

3*(9+1)-6 -> 3*(10)-6

Then do multiplication:

3*(10)-6 -> (30)-6

Then complete it with subtraction:

(30)-6 -> (24)

So your answer would be 24!

PEMDAS= Parenthesis, Exponents, Multiplication, Division, Add, Subtract.

7 0
3 years ago
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2) A company used 24 lemons to make 4 bottles of lemonade. Write an equation that
boyakko [2]

Answer:

Step-by-step explanation:

4 0
3 years ago
Sean bought a 6 inch sub. He ate 3 3/4 inches. How much sub does he have left in the simplest form.
irinina [24]

Answer: 2 1/2

hope this helps

4 0
3 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
Read 2 more answers
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