Based on the information provided and the requirements to organize the students, Jon most likely has 23 students.
<h3>How many students are needed to organize them in a rectangular grid?</h3>
In general, Jon will need a number that is not prime as this type of number will not allow him to complete all the grid.
<h3>Which are possible numbers?</h3>
20 = A rectangular grid of 5 x 4 seats can be arranged
21= A rectangular grid of 7 x 3 can be arranged
22 = A rectangular grid of 2 x 11 can be arranged
23 = It is impossible to organize 23 seats in a rectangular grid without gaps
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The answer is B) x>3
13x - 4 < 12x - 1
13x > 12x + 3
x > 3
1. Answer: Vertical shift up 3 units and vertical stretch by factor of 2
<u>Step-by-step explanation:</u>
f(x) = √x
g(x) = 2√x + 3
- adding 3 is a vertical shift up 3 units
- multiplying by 2 is a vertical stretch by factor of 2
2. Answer: Domain: [0, ∞)
Range: [3, ∞)
<u>Step-by-step explanation:</u>
g(x) = 2√x + 3
Domain: The restriction on "x" is that the radical must be greater than or equal to 0. So, x ≥ 0 Interval Notation: [0, ∞)
Range: Since the radical must be greater than or equal to 0, then 2√x is also greater than or equal to 0. Add 3 to that and y ≥ 3. Interval Notation: [3, ∞)
Answer:
10.
here,
h=c
b=5
p=12
,we know that,
h²=b²+p²(pythagoras theorum )
c=5²+12²
c=25+144
c=169
hence the value of c is 169.