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nata0808 [166]
2 years ago
8

What are the difference in finding the cirumference circle and finding the area of circle

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
7 0

Answer:

the circumference is the total distance round a circle but the are is a measure of a space or region inside the circle but circumference is around it

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max said that 36594 is less than 5980 because 3 is less then 5 describe max's error and give the correct answer
Verizon [17]
He was wrong because, although three is greater than five, the value of the three is in the ten thousands place, while the five is in the thousands place. Therefore, the correct answer would be that 36594 is greater than 5980.
4 0
3 years ago
What is 0.31 rounded to the nearest tenth
Tomtit [17]

0.31 rounded to the nearest tenth would be 0.3

This Chart should help you in the future:

8 0
2 years ago
Evaluate the power: (−3)^4<br> A. 81<br> B. -81<br> C. 243<br> D. -331
Agata [3.3K]

Answer:

The answer is 81.

Step-by-step explanation:

Since the power of 4 is even, the result will be positive.

{3}^{4}

Simplify.

81

<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>Option</u><u> </u><u>A</u><u>)</u><u> </u><u>81</u><u>.</u>

7 0
3 years ago
Read 2 more answers
What is 9x25= twenty-fives
Amanda [17]
9×29 equals 225 = two hundred twety-five
7 0
3 years ago
4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B
AleksAgata [21]

Answer:

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

Step-by-step explanation:

1) Data given and notation  

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

\hat p=\frac{63}{200}=0.315 estimated proportion of lawyers had used some form of advertising for their business

p_o=0.25 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

8 0
3 years ago
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