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Elena L [17]
3 years ago
7

Please need help ASAP I will give brainliest

Mathematics
1 answer:
NARA [144]3 years ago
5 0

Answer:

for number 4 i think it is option 3

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The absolute value function, f(x) = |x + 2|, is shown. If the graph is reflected over the x-axis, what is the domain of the func
inna [77]

Answer:

Step-by-step explanation:

given f(x)=|x+2 |

after reflection f'(x)=-|x+2|

domain is same.

domain is all real numbers.

5 0
3 years ago
Ashley has finished 7/25 of her homework what percentage of the homework does Ashley still need to finish
ludmilkaskok [199]

Answer:

72 percent

Step-by-step explanation:

7/25, x 4 to get a fraction of 100

28/100

100 - 28 = 72

72 percent

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2 years ago
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What is the y-intercept in the equation y = 4x-3?​
timofeeve [1]

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-3

Step-by-step explanation:

y = mx + b

b is the y-intercept

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2 years ago
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The sum of two numbers is 50 and the difference is 10. What are the numbers?
Black_prince [1.1K]

Answer:

I believe the answer is 20 and 30

5 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
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