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3 years ago

Answer please BEN......

Mathematics

1 answer:

Sati [7]3 years ago

7 0

Answer:

$12x\leq 24$ ; $x\leq 2$

Step-by-step explanation:

So you have 12 math problems that each take x amount of minutes, and have 24 minutes to finish them. Remember, you can't exceed the 24 minutes (but you are allowed to equal that time). So:

$12x\leq 24$

Then you can simplify by dividing both sides by 2:

$x\leq 2$

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What is greater one inch or one centimeter

maria [59]

One inch is greater than one centimeter

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3 years ago

Read 2 more answers

A total of 815 tickets were sold for the school play. They were either adult tickets or student tickets. There were 65 more stud

kvv77 [185]

Answer:

375 Adult Tickets.

Step-by-step explanation:

Here, we can simply set up an equation using variable x in place of the unknown student/adult tickets.

x = # of adult tickets sold

x + 65 = # of student tickets sold.

1) x + x + 65 = 815 (set both ticket amounts equal to the total)

2) 2x + 65 = 815 (added common variables together)

3) 2x = 750 (negated the +65, subtracted it from both sides)

4) x = 375 (divided both sides by 2)

5) 815 - 375 = 440 (subtracted the x from the total number of adult tickets, to recieve the amount of childrens' tickets.

Therefore,

Since there were fewer adult tickets sold (-65), 375 is the number of adult tickets, and 440 is the number of student tickets.

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3 years ago

9. If ground beef costs $4.98 for 3 pounds, then what is the unit rate (cost per

Drupady [299]

Answer:

1.66 pounds

Step-by-step explanation:

4.98 dollars divided by 3 pounds

4 0

3 years ago

A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec

Paraphin [41]

Answer:

A. The solutions are $x=3i,\:x=-3i$ .

B. The factored form of the quadratic expression $x^2+9=(x-3i)(x+3i)$

Step-by-step explanation:

A. To find the solutions to the quadratic equation $x^2+9=0$ you must:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}$