A mixed number is one that has an integer along with a proper fraction, so that would be (for this improper fraction):
50/12 = 4 1/6
12 goes into 50, 4 times with a remainder of 2
you get: 4 and 2/12, but 2/12 can be reduced further to 1/6
so that's how i got the answer of 4 1/6
Answer:
-3x^4 - 13x^3 + 14x - 7
Step-by-step explanation:
(5x^4 – 9x^3 + 7x – 1) + (-8x^4 + 4x^2 – 3x + 2) - (-4x^3 + 5x - 1)(2x – 7)
simplify multiplied terms
(-4x^3 + 5x - 1)(2x – 7)
(-4x^3+10x-8)
group like terms together
(5x^4-8x^4) + (-9x^3-4x^3) + (7x-3x+10x) + (-1+2-8)
simplify grouped terms
-3x^4 - 13x^3 + 14x - 7
Answer:
<h2>a) 10⁶metres</h2><h2>b) 10¹⁸metres</h2>
Step-by-step explanation:
Given One terameter equals 10¹² meters. One micrometer equals 10⁻⁶ meter, one nanometer equals 10⁻⁹meter;
a) The product of one terameter and one micrometer will be expressed as;
10¹² * 10⁻⁶
Since the both have the same base, we will add their power according to one of the law in indices as shown
10¹² * 10⁻⁶ = 10⁻⁶⁺¹²
= 10⁶metres
b) The quotient of one terameter and one micrometer can be gotten by taking their ratio as shown below;
Note that when taking the quotient, the power are subtracted

The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>

Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib

For Addison h=85(1/3)

Subtracting both distances we get

Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
brainly.com/question/1392973
Answer:
Step-by-step explanation:
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