find two consecutive odd integers that 7 times the smaller integer is 61 more than 2 times the larger integer.
1 answer:
Answer:
x = 13 smaller integer
x + 2 = 15 the other integer
Step-by-step explanation:
x = the smaller integer
x + 2 = the next integer
7(x) = 61 + 2(x + 2)
7x = 61 + 2x +4
5x = 61 + 4
5x = 65
x = 13 smaller integer
x + 2 = 15 the other integer
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Answer:
17*17*17= 4913
4 * 4 * 4 * 4 * 4 = 1024.
Hope this helps.
The value of x in the traingle is 5
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Answer:
The value of x is 8
Step-by-step explanation:
What’s the answer choices ?
It’s going to be -2 because the y intercept is when x=0.
