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3 years ago

Simplify the expression below.

Mathematics

1 answer:

statuscvo [17]3 years ago

6 0

Answer:

(a)

Step-by-step explanation:

x^-4 + -4 + -4 + -4 + -4 + -4 = x^-24

hope it helps :)

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Simplify: 10 - 2(3+4)*

melomori [17]

Answer: -4

Step-by-step explanation:

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2 years ago

Write the number shown in standard notation. 1.02 x 10 First Correct answer gets Brainliest

SIZIF [17.4K]

Answer:

1.02×10¹ = 10.2

Step-by-step explanation:

We have given a number in scientific notation as follows 1.02×10¹

We need to convert it into standard notation.

1 is in ones place, 0 is in tenths place and 2 is in hundredths place.

$1.02\times 10^1=\dfrac{102}{100}\times 10\\\\=\dfrac{102}{10}\\\\=10.2$

So, the standard notation of 1.02×10¹ is 10.2

7 0

3 years ago

It is known that a cable with a cross-sectional area of 0.300.30 sq in. has a capacity to hold 2500 lb. If the capacity of the

vesna_86 [32]

Answer:

0.84 square in

Step-by-step explanation:

Since the capacity of the cable is proportional to its cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold

2500 / 0.3 = 8333.33 lb/in

To old 7000 lb it the cross-sectional area would need to be

7000 / 8333.33 = 0.84 square in

5 0

2 years ago

Read 2 more answers

1+16=14+2 is this true or false

il63 [147K]

Answer:

False

Step-by-step explanation:

1+16=17

14+2=16

17 does not = 16

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!

Nitella [24]

Answer:

The radius of a sphere is 2 millimeters

The surface area of a sphere is 50.24 square millimeters.

The circumference of the great circle of a sphere is 12.56 millimeters.

Step-by-step explanation:

<u><em>Verify each statement</em></u>

case A) The radius of a sphere is 8 millimeters

The statement is false

we know that

The volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$V=100.48/3\ mm^{3}$

$\pi =3.14$

substitute and solve for r

$100.48/3=\frac{4}{3}(3.14)r^{3}$

$r^{3}=(100.48)/(4*3.14)$

$r=2\ mm$

case B) The radius of a sphere is 2 millimeters

The statement is True

(see the case A)

case C) The circumference of the great circle of a sphere is 9.42 square millimeters

The statement is false

The units of the circumference is millimeters not square millimeters

The circumference is equal to

$C=2\pi r$

we have

$r=2\ mm$

$\pi =3.14$

substitute

$C=2(3.14)(2)$

$C=12.56\ mm$

case D) The surface area of a sphere is 50.24 square millimeters.

The statement is True

Because

The surface area of the sphere is equal to

$SA=4\pi r^{2}$

we have

$r=2\ mm$

$\pi =3.14$

substitute

$SA=4(3.14)(2)^{2}$

$SA=50.24\ mm^{2}$

case E) The circumference of the great circle of a sphere is 12.56 millimeters.

The statement is true

see the case C

case F) The surface area of a sphere is 25.12 square millimeters

The statement is false

because the surface area of the sphere is $SA=50.24\ mm^{2}$

see the case D

7 0

3 years ago

Read 2 more answers