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3 years ago

Compare FractionsCompare. Write >,<, or =1/5 1/15

Mathematics

1 answer:

defon3 years ago

4 0

Answer:

$\frac{1}{5} \: and \: \frac{1}{15}$

Both of these must have similar denominators:

$\frac{3}{15} \: and \: \frac{1}{15} \\ \frac{3}{15} \: i s \: \: more \: than \: \frac{1}{15} \\ \frac{3}{15} > \frac{1}{15}$

Good luck!

Intelligent Muslim,

From Uzbekistan.

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Step-by-step explanation:

We are given the following:

I. A score of 2.6 on a test with $\bar X$ = 5.0 and s = 1.6

II. A score of 650 on a test with $\bar X$ = 800 and s = 200

III. A score of 48 on a test with $\bar X$ = 57 and s = 6

And we have to find that which score indicates the highest relative position.

For finding in which score indicates the highest relative position, we will find the z score for each of the score on a test because the higher the z score, it indicates the highest relative position.

The z-score probability distribution is given by;

Z = $\frac{X-\bar X}{s}$ ~ N(0,1)

where, $\bar X$ = mean score

s = standard deviation

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The z-score of First condition is calculated as;

Since we are given that a score of 2.6 on a test with $\bar X$ = 5.0 and s = 1.6,

So, z-score = $\frac{2.6-5}{1.6}$ = -1.5 {where $\bar X = 5.0$ and s = 1.6 }

The z-score of Second condition is calculated as;

Since we are given that a score of 650 on a test with $\bar X$ = 800 and s = 200,

So, z-score = $\frac{650-800}{200}$ = -0.75 {where $\bar X = 800$ and s = 200 }

The z-score of Third condition is calculated as;

Since we are given that a score of 48 on a test with $\bar X$ = 57 and s = 6,

So, z-score = $\frac{48-57}{6}$ = -1.5 {where $\bar X = 57$ and s = 6 }

AS we can clearly see that the z score of First and third condition are equally likely higher as compared to Second condition so it can be stated that A score of 2.6 on a test with $\bar X$ = 5.0 and s = 1.6 and A score of 48 on a test with $\bar X$ = 57 and s = 6 indicate the highest relative position.

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