Okay, so we know that the perimeter of the square is 20. Since a square has 4 equal sides to find the length of one side, 20/4. Each side is equal to five. Look at each of the coordinates and put them respectively into a graph in your mind. w(3,2) (bottom left) x(3,7) (top left) Y(8,7) (top right). Now we know we need to find the bottom right coordinate. Being that both of the coordinates on the left have the same x value we can justify that the coordinates on the right have the same X value also. we can say this same thing for the y coordinate. Since both coordinates on the top of the square have the same Y value, we can justify that the coordinates on the bottom have the same Y value. So taking the coordinates we now are the same, the answer is Z(8,2). We can check his by seeing if the distance if five from each of the adjacent coordinates. If you have any questions comment below.
Answer:
(0,0)
Step-by-step explanation:
The coordinates of C now are (-7,-5).
Moving C -3 on the x-axis will move -7 - 3 = -10. C is now located on (-10,-5).
Moving C +5 on the y-axis will move -5 + 5 = 0. C is now located on (-10,0).
Moving C on the y-axis +10 will move -10 + 10 = 0. C is now located on (0,0).
C is translated to (0,0).
Answer : The two correct options are,
3.4a + 5.6b
5.6b + 3.4a
Step-by-step explanation :
The given expression is:
(-2.4a - 1.8b) - (-3.8a - 4.4b) + (2.0a + 3.0b)
First we have to open the brackets.
⇒ -2.4a - 1.8b + 3.8a + 4.4b +2.0a + 3.0b
Now keep like terms together.
⇒ -2.4a + 3.8a +2.0a + 3.0b - 1.8b + 4.4b
By subtraction or addition, we get:
⇒ 3.4a + 5.6b
or,
⇒ 5.6b + 3.4a
Hence, the expressions that equivalent to the given expression are, 3.4a + 5.6b and 5.6b + 3.4a
Step-by-step explanation:
2 !!!
hope it helps
have a great day:))
Answer:
The sample loses 
of its mass every days.
Step-by-step explanation:
Expression that shows the relation between final mass of the element after 't' days is,
M(t) = 
If M(t) = two third of the initial mass [After the loss of one third of the initial mass remaining mass of the element = 1 - = 
rd of the initial mass]
![\frac{2}{3}=[(\frac{2}{3})^3]^t](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%3D%5B%28%5Cfrac%7B2%7D%7B3%7D%29%5E3%5D%5Et)
By comparing powers on both the sides
3t = 1
t = day
Therefore, The sample loses of its mass every days.
