At Rose State College Allison Wells received the following grades her accounting class 93, 60, 78, 89 ,78 and 82 Allison's instr
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Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: fitness of a line of E. coli grown on an acidic environment.
n= 6 E. coli lines
Recorded fitness for each line: 1.24, 1.22, 1.23, 1.24, 1.18, 1.09
The relative fitness of 1 indicates that both bacteria types are equally fit.
A relative fitness larger than 1 indicates that the acid-evolved line is more fit than the parental line kept at neutral pH when both are grown in acidic conditions.
Meaning that if the average fitness of the E. coli lines grown on an acidic environment is greater than 1 then they are better adjusted to live in acidic conditions, symbolically: μ > 1
The statistic hypotheses are:
H₀: μ ≤ 1
H₁: μ > 1
α: 0.05
Assuming that the variable has a normal distribution you have to apply a one-sample t-test:
X[bar]= 1.20
S= 0.06
The p-value for this test is 0.0002
Since the p-value= 0.0002 is less than α:0.05 the decision is to reject the null hypothesis.
Then at a 5% significance level, there is significant evidence to conclude that the bacteria evolved in acidic pH are better adapted to acidic conditions.
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Answer:
There is no need to call for election.
Step-by-Step Explanation
Surveys are based on probability or statistics. It serves as a standard tool for experimental research in marketing, social sciences and official data statistics.
Since 8 out of 40 members of the Sweetheart Union will sign the petition, the percentage of those who will sign the petition is calculated below:
Based on the sample survey, only 20 percent of the members will sign the petition. Since, in the sample, the number of those who will sign is less than 33%, the union should be told that there is no need for the National Labor Relations Board to call for the election.