Answer:
Step-by-step explanation:
Given that an automatic machine is set to fill bags of dog food with exactly 25 pounds on average with a standard deviation of 0.5 pounds.
Sample size = n =100
x bar = 24.85 pounds
Sample std error = 
Hypotheses:
(Two tailed test at 5% level)
Mean difference =0.15
Test statistic = mean diff/se = 3
Since population std dev is known z test can be used
p value =0.0000
Since p <0.05 we find that the bag does not contain exactly 25 pounds.
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Because the ratio is 1 to 3. It means that For every one apple there are 3 oranges. So If there are 2 apples, there would n 6 oranges. If there are twelve apples, there would be 36 oranges. To find the number of oranges for the amount of apples, just multiply the number of apples by 3.
