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Charra [1.4K]
3 years ago
12

An expression is shown below:

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Given:

The given expression is:

6x^2y-3xy-24xy^2+12y^2

To find:

Part A: The expression by factoring out the greatest common factor.

Part B: Factor the entire expression completely.

Solution:

Part A:

We have,

6x^2y-3xy-24xy^2+12y^2

Taking out the highest common factor 3y, we get

=3y(2x^2-x-8xy+4y)

Therefore, the required expression is 3y(2x^2-x-8xy+4y).

Part B:

From part A, we have,

3y(2x^2-x-8xy+4y)

By grouping method, we get

=3y(x(2x-1)-4y(2x-1))

=3y(x-4y)(2x-1)

Therefore, the required factored form of the given expression is 3y(x-4y)(2x-1).

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At the beginning of each year for 14 years, Sherry Kardell invested $400 that earns 10% annually. What is the future value of Sh
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Hmm if I'm not mistaken, is just an "ordinary" annuity, thus 

\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]
\\\\\\

\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array} &
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &400\\
r=rate\to 10\%\to \frac{10}{100}\to &0.1\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, so once}
\end{array}\to &1\\

t=years\to &14
\end{cases}
\\\\\\
A=400\left[ \cfrac{\left( 1+\frac{0.1}{1} \right)^{1\cdot 14}-1}{\frac{0.1}{1}} \right]

3 0
3 years ago
Read 2 more answers
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Drag the tiles to the correct boxes to complete the pairs, not all tiles will be used.
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Step-by-step explanation:

6 0
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Dafna11 [192]

Answer:

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Step-by-step explanation:

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3 years ago
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