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Oksanka [162]
3 years ago
15

Questions are cool.

Mathematics
1 answer:
Zarrin [17]3 years ago
5 0

Answer:

the answer to this question is 785

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I need help with a & c please!
jeka94
The answer to a is 12 and the and the answer to c is367
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3 years ago
Wish I didn’t have to say anything because the question is always in the picture
joja [24]

Answer:

The slope in Function A is greater :)

Step-by-step explanation:

Slope in A: 3

Slope in B: 1

5 0
3 years ago
Evaluate if k = 3.<br> k2 + 5 = [?]
Grace [21]

Answer:

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Hope this helps you and good luck :)

Step-by-step explanation:

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Step-by-step explanation:

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3 0
3 years ago
How do you do this problem?
Vadim26 [7]

Answer:

Your answer is absolutely correct

Step-by-step explanation:

The work would be as follows:

\int _0^{\sqrt{\pi }}4x^3\cos \left(x^2\right)dx,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=> 4\cdot \int _0^{\sqrt{\pi }}x^3\cos \left(x^2\right)dx\\\\\mathrm{Apply\:u-substitution:}\:u=x^2\\=> 4\cdot \int _0^{\pi }\frac{u\cos \left(u\right)}{2}du\\\\\mathrm{Apply\:Integration\:By\:Parts:}\:u=u,\:v'=\cos \left(u\right)\\=> 4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\int \sin \left(u\right)du\right]^{\pi }_0\\\\

\int \sin \left(u\right)du=-\cos \left(u\right)\\=> 4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\left(-\cos \left(u\right)\right)\right]^{\pi }_0\\\\\mathrm{Simplify\:}4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\left(-\cos \left(u\right)\right)\right]^{\pi }_0:\quad 2\left[u\sin \left(u\right)+\cos \left(u\right)\right]^{\pi }_0\\\\\mathrm{Compute\:the\:boundaries}:\quad \left[u\sin \left(u\right)+\cos \left(u\right)\right]^{\pi }_0=-2\\=> 2(-2) = - 4

Hence proved that your solution is accurate.

3 0
4 years ago
Read 2 more answers
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