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uranmaximum [27]
2 years ago
9

B. f(-3) = 1, f(5) = -2

Mathematics
1 answer:
iVinArrow [24]2 years ago
5 0

Answer:

oh u most likely already answered it, it was an hour

Step-by-step explanation:

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5) Ziegler is using paper for an art project
lord [1]

Answer:

9.5 * 10^-2 mm

Step-by-step explanation:

To find the total thickness, we proceed to add the two thickness that we have

Mathematically, this will be;

0.025 mm + 7 * 10^-2 mm

7 * 10^-2 mm = 0.07

So we have;

0.025 mm + 0.07 mm = 0.095

In scientific notation, this is 9.5 * 10^-2 mm

6 0
3 years ago
Trey is solving his equation, and the last line of his work is "-2 = 2". What does this mean?
oksian1 [2.3K]

Answer:

it means that his equation is not true.

Step-by-step explanation:

-2=2 is obviously incorrect, so we must assume that the equation isn't true.

3 0
3 years ago
I need this answered as soon as possible
Rzqust [24]

Answer:

34

Step-by-step explanation:

basically you need to actually put something in the black photo there

8 0
3 years ago
Read 2 more answers
How do you count dog years
k0ka [10]

Answer:

15 human years is 1 year for a medum sized dog

the second year for a dog is 9 years for a human

after that each human year would be 5 years for a dog estimated

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If A denotes some​ event, what does Upper A overbar ​denote? If ​P(A)equals0.999​, what is the value of ​P(Upper A overbar​)? Wh
meriva

Answer:

<h3>The event P(\overline{A}) denotes the complement of event A.</h3><h3>The value of P(\overline{A}) is 0.001</h3>

Step-by-step explanation:

Given that A denotes some event .

And also given that P(A)=0.999

<h3>To find the value of P(\overline{A}) :</h3>

Here the event P(\overline{A}) denotes the complement of event A Therefore P(\overline{A}) contains all the events that does not occur in A.

We know that the total probability is 1

So we have that

P(A)+P(\overline{A})=1

P(\overline{A})=1 -P(A)

=1-0.999

=0.001

Hence the complement of event A is P(\overline{A})=0.001

<h3>Therefore the value is P(\overline{A})=0.001</h3>

6 0
2 years ago
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