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Aleksandr [31]
2 years ago
8

The radius of the circle below is 22 mm. Calculate the area of the circle. Give your answer in mm² to 1 d.p.​

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
6 0

Answer:

1520.7mm^2

Step-by-step explanation:

area of a circle= πr^2

area of the circle = 3.142×22^2

area of the circle= 3.142×22×22= 1,520.728

area to 1dp= 1520.7mm^2

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alukav5142 [94]

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4 0
2 years ago
The resting heart rate of 60 patients is shown in the frequency table below.
Murrr4er [49]

The standard deviation is 9.27. The typical heart rate for the data set varies from the mean by an average of 9.27 beats per minute.

<h3>How to determine the standard deviation of the data set?</h3>

The dataset is given as:

Heart Rate  Frequency

60 1

65 3

70 4

75 12

80 8

85 15

90 9

95 5

100 3

Calculate the mean using

Mean = Sum/Count

So, we have

Mean = (60 * 1 + 65 * 3 + 70 * 4 + 75 * 12 +  80 * 8 +  85 * 15 +  90 * 9 +  95 * 5 + 100 * 3)/(1 + 3 + 4 + 12 + 8 + 15 + 9 + 5 + 3)

Evaluate

Mean = 82.25

The standard deviation is

\sigma = \sqrt{\frac{\sum f(x - \bar x)^2}{\sum f -1}}

So, we have:

SD = √[1 * (60 - 82.25)^2 + 3 * (65 - 82.25)^2 + 4 * (70 - 82.25)^2 + 12 * (75 - 82.25)^2 + 8 * (80 - 82.25)^2 +  15 * (85 - 82.25)^2 +  9 * (90  - 82.25)^2 + 5 * (95 - 82.25)^2 + 3 * (100 - 82.25)^2)]/[(1 + 3 + 4 + 12 + 8 + 15 + 9 + 5 + 3 - 1)]

This gives

SD = √85.9533898305

Evaluate

SD = 9.27

Hence. the standard deviation is 9.27. The typical heart rate for the data set varies from the mean by an average of 9.27 beats per minute.

Read more about standard deviation at:

brainly.com/question/4079902

#SPJ1

5 0
1 year ago
On Monday, your bank account balance was $12.58. Because you didn't realize this, you wrote a check for $30.72 for groceries. Th
Ivenika [448]

the balance would probably be $37

6 0
3 years ago
Two and one ninth minus seven sixth equals
tatiyna
.944
2 1/9 = 2.111
7/6 = 1.167
2.111-1.167= .944

4 0
2 years ago
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Can you please help me i need to factor this equation but i am stuck in this type of question: c^2-9cd+18d^2
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C^2-3cd-6cd+18d^2
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3 years ago
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