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zepelin [54]
3 years ago
11

A student is preparing to bake a cake at home and places several ingredients on the countertop to use. First he preheats the ove

n to 175C, then mixes all of the ingredients together. He pours all of the cake batter into 2 pans and bakes for 1 hour. The cake layers are allowed to cool for 15 minutes. Which of the following indicates that a chemical change occurred?
Physics
1 answer:
Evgen [1.6K]3 years ago
7 0

Answer:

baking the cake batter

Explanation:

Baking the cake batter will indicate that chemical change has occurred here. What is a chemical change?

  • A chemical change is one in which a new kind of matter is formed.
  • It is usually accompanied by energy either evolution or absorption of energy in form of heat or light or both.
  • The process is irreversible.
  • When the batter bakes, a new substance different from the cake mix is obtainable.
  • We cannot get back the ingredient from this baked cake. It is impossible.
  • This is good indicator of chemical change.
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A crowbar makes our work easier by multiplying effort true or false​
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Answer:

True

Explanation:

A crowbar makes our work easier by multiply effort because it belongs to first class lever.

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A student drops an egg from the roof of their house onto a trampoline. The egg feels a change in momentum of 2.2 kg^ * m/s in 1.
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8 0
2 years ago
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3 0
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When you eat a candy bar, your body oxidizes glucose to get energy. where does this energy come from? kinetic energy of the gluc
babymother [125]
The correct answer is
<span>"chemical bonds within the glucose molecules "

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8 0
2 years ago
A 3.0 m tall, 40 cm diameter concrete column supports a 235,000 kg load. by how much is the column compressed? assume young's mo
statuscvo [17]
The Young modulus E is given by:
E= \frac{F L_0}{A \Delta L}
where 
F is the force applied
A is the cross-sectional area perpendicular to the force applied
L_0 is the initial length of the object
\Delta L is the increase (or decrease) in length of the object.

In our problem, L_0 = 3.0 m is the initial length of the column, E=3.0 \cdot 10^{10}N/m^2 is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:
r= \frac{d}{2}= \frac{40 cm}{2}=20 cm=0.2 m
and the cross-sectional area is
A=\pi r^2 = \pi (0.20 m)^2=0.126 m^2
The force applied to the column is the weight of the load:
W=mg=(235000 kg)(9.81 m/s^2)=2.305 \cdot 10^6 N

Now we have everything to calculate the compression of the column:
\Delta L =  \frac{F L_0}{EA}= \frac{(2.305\cdot 10^6 N)(3.0 m)}{(3.0\cdot 10^{10}N/m^2)(0.126 m^2)} =1.83\cdot 10^{-3}m
So, the column compresses by 1.83 millimeters.
3 0
3 years ago
Read 2 more answers
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