Answer:
73.67 m
Explanation:
If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:
,
Where 
its our initial height, 
our initial speed, a the acceleration and t the time that has passed.
For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.
We can plug this values in our equations, to obtain:
note that the acceleration point downwards, hence the minus sign.
Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:
and obtain:
Plugin this time on our first equation we find:
Answer:
d. Direction and magnitude
Explanation:
The two components of a vector are its magnitude and direction.
Magnitude is the quantity of the substance
Direction is the path.
- Other quantities are called scalar quantities.
- Scalar quantities have only magnitude but no direction.
Examples of vector quantities are velocity, displacement, acceleration.
Question
Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles travelled in a straight line and some were deflected at different angles.
Which statement best describes what Rutherford concluded from the motion of the particles?
A) Some particles travelled through empty spaces between atoms and some particles were deflected by electrons.
B) Some particles travelled through empty parts of the atom and some particles were deflected by electrons.
C) Some particles travelled through empty spaces between atoms and some particles were deflected by small areas of high-density positive charge in atoms.
D) Some particles travelled through empty parts of the atom and some particles were deflected by small areas of high-density positive charge in atoms.
Answer:
The right answer is C)
Explanation:
In the experiment described above, a piece of gold foil was hit with alpha particles, which have a positive charge. Alpha particles <em>α</em> were used because, if the nucleus was positive, then it would deflect the positive particles. The principles of physics posit that electric charges of the same orientation repel.
So most as expected some of the alpha particles went right through meaning that the gold atoms comprised mostly empty space except the areas that were with a dense population of positive charges. This area became known as the "nucleus".
Due to the presence of the positive charges in the nucleus, some particles had their paths bent at large angles others were deflected backwards.
Cheers!
So to solve for this problem, this is computed by the
following steps:
Vp / Vs ( = Np / Ns
Where:
Vp = Voltage Primary
Vs = Voltage Secondary
Np = Turn ratio Primary
Ns = Turn ratio Secondary.
So plugging in our values: <span>
110 / 4.9 = N</span>p / Ns<span>
N</span>p / Ns =22.44, so <span>the answer is 22 coils.</span>
