3 years ago

What is the equation graph below?

Mathematics

1 answer:

GaryK [48]3 years ago

6 0

Answer: y =7/4x

Step-by-step explanation:

The y-intercept is 0. To find the slope, do the change in y over the change in x. At the point on the graph, there is a slope of 14/8 = 7/4

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Shalnov [3]

$x^2+3x-5=0\\\\a=1;\ b=3;\ c=-5\\\\b^2-4ac=3^2-4\cdot1\cdot(-5)=9+20=29\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-3-\sqrt{29}}{2\cdot1}=\dfrac{-3-\sqrt{29}}{2}\approx-4.19\\\\x_2=\dfrac{-3+\sqrt{29}}{2\cdot1}=\dfrac{-3+\sqrt{29}}{2}\approx1.19$