Question

Can someone help me please

Answer 1

Answer: $\frac{1}{\sqrt{5}}$ or $\frac{\sqrt{5}}{5}$

Step-by-step explanation:

The sine of an angle is equal to the opposite of leg of the triangle over the hypotenuse. Since the side opposite angle A is 5, and the hypotenuse is $5\sqrt{5}$, then sinA = $\frac{5}{5\sqrt{5} }$, simplified to $\frac{1}{\sqrt{5}}$ and rewritten as $\frac{\sqrt{5}}{5}$

Answer 2

Step-by-step explanation:

Since Sin in your trigonometric ratio is sin¤= opp/hyp

where the b the line the right angle facing is hypothenus.your opposite is then line a

a= 5

b =5root5

using the trig ratio SinA= a/b= 5/5root5

SinA= 1/root5

SinA=.44727

A= Arcsin0.44727

A=26.5°