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levacccp [35]
3 years ago
13

[repost with picture] question #4, show steps please

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

C

Step-by-step explanation:

We are given the graph of f and that:

\displaystyle g(x)=\int_0^xf(t)\, dt

And we want to determine the values of x for which g has a point of inflection.

By the Fundamental Theorem of Calculus:

g'(x)=f(x)

Thus:

g''(x)=f'(x)

g(x) has a point of inflection if and only if g''(x) = 0 and g''(x) changes signs around the point.

Since g''(x) = f'(x), g''(x) = 0 when f'(x) is 0. This happens at x = 2 and x = 5.

And at both x = 2 and x = 5, f'(x) changes signs before and after. Thus, g''(x) has inflection points at both x = 2 and x = 5.

The correct answer is C.

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Lubov Fominskaja [6]

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"B" is the answer.

I hope this helps!

Step-by-step explanation: A= s^2 <- for a square

A= 1/2*b*h <- for a triangle

A= 4^2= 16

A= 1/2*8*6 (The whole height is 8 yd)

A= 1/2*48

A= 24

24+16= 40 yd^2

"B" is the answer.

I hope this helps!

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3 years ago
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Answer:

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Step-by-step explanation:

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Hope this helps!! Have a nice day!!
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