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3 years ago

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A tank contains 1000L of pure water. Brine that contains 0.02kg of salt per liter enters the tank at a rate of 5L/min. Also, bri

ne that contains 0.07kg of salt per liter enters the tank at a rate of 10L/min. The solution is kept thoroughly mixed and drains from the tank at a rate of 15L/min. Answer the following questions.
a. How much salt is in the tank after t minutes?
b. How much salt is in the tank after 4 hours?

1 answer:

tankabanditka [31]3 years ago

3 0

Answer:

51.877 kg

Step-by-step explanation:

a

See attachment for calculations

b

The amount of salt in the tank after 4 hours is gotten by simply replacing t in the equation from a, with 4 hours. Since the t gotten in a above is in minutes, we'd convert hours to minute as well. If we do that, we have

t = 4 hours = 4 * 60 minutes = 240 minutes

y = 160/3 (1 - e^((-3 * 240)/200))

y = 160/3 (1 - e^(-720/200))

y = 160/3 (1 - 0.0273)

y = 160/3 (0.9727)

y = 51.877 kg

Therefore, the amount of salt in the tank after 4 hours is 51.877 kg

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Answer:

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Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for $x$ days.

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The tour is extended by 4 days.

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On extension, his daily expense is cut by $3

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Simplifying by using distribution (FOIL).

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So, we have the equation as:

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Multiplying each term with $x$ to remove fractions.

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Subtracting $348x$ both sides

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Dividing each term with -3.

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Answer:

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