Answer:
We balance chemical equations due to the law of conservation of mass, which states that mass can neither be created or destroyed. Therefore, in a chemical reaction, the total mass of the reactants must be equal to the total mass of the products. Balancing equations accounts for the total mass of the reactants and the total mass of the products.
Explanation:
We balance chemical equations due to the law of conservation of mass, which states that mass can neither be created or destroyed. Therefore, in a chemical reaction, the total mass of the reactants must be equal to the total mass of the products. Balancing equations accounts for the total mass of the reactants and the total mass of the products.
It is b the metric system
Answer:
Given
[HONH2] = 0.45M
[OH-] = 5.26 x 10-6 M
HONH2 + H2O -------------> HONH3+ + OH-
Initial 0.45 55 0 0
at equilibrium 0.45-x 55-x x x
Given
[OH-] = x = 5.26 x 10-6 M
Therefore [HONH3+] = x = 5.26 x 10-6 M
pOH = -log[OH-] = -log(5.26 x 10-6) = 5.279
=> pH = 14- pOH = 8.72
From hendersen-hasselbach equaiton
8.72 = pKa + log(0.45/5.26 x 10-6)
=> pKa = 3.788
=> pKb = 14-3.788 = 10.21
percent of ionization = 5.26 x 10-6 * 100/0.45 = 1.17 x 10-3 %
concentration of NaOH required to make the same pH= [OH-] = 5.26 x 10-6 M
Percent of ionization of NaOH = [OH-]*100/NaOH = 5.26 x 10-6 *100/5.26 x 10-6 = 100%
1.35 Litres of water need to be added to 750 ml of a 2.8 m hcl solution to make a 1.0 m solution.
Use the following relation:
M1V1=M2V2
Where M is molarity, V is volume and 1 is initial and 2 is the final conditions. Solving for V(2)
M1=2.8 M,V1=750 mL;M2=1.0 M
(2.8 M)×(750 mL)=(1.0 M)×V2
V2=(2.8 M)×(750 mL)(1.0 M) = 2100 mL = 2.1 L
Therefore, Volume of water to be added =2.1 L−0.75 L=1.35 L
Learn more about the Molarity with the help of the given link:
brainly.com/question/19517011
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