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3 years ago

What is defined as the number of atoms surrounding an atom in a crystal lattice?

Chemistry

1 answer:

Simora [160]3 years ago

4 0

Answer:

coordination number

Explanation:

Coordination number -

In a crystal lattice , the number of atoms that are surrounded to a particular atom , is referred to as the coordination number of the crystal.

In the field of crystallography and chemistry , it is also called the ligancy.

In coordination chemistry , the number of ligands attached to the central metal atom is also known as the coordination number of the coordination compound.

Hence, from the given statement of the question,

The correct term is coordination number.

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3 years ago

Reason why chemistry is studied

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3 years ago

A gas has a volume of 1.75L at -23C and 150.0kPa. At what temperature would the gas occupy 1.30L at 210.0kPa?

Katen [24]

Answer:

T2 = 260 K

Explanation:

Given data:

P1 = 150.0 k Pa

T1 = (-23+ 273.15) K = 250.15 K

V1 = 1.75 L

P2 = 210.0 kPa

V2 = 1.30 L

To find:

T2 = ?

Formula:

$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$

$T_2 = \frac{P_2 V_2 T_1}{P_1 V_1}$

Calculation:

T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)

T2 = 260 K

8 0

3 years ago

Complete combustion of 5.90 g of a hydrocarbon produced 18.8 g of CO2 and 6.75 g of H2O.

Inessa05 [86]

First we have to find moles of C:
Molar mass of CO2:
12*1+16*2 = 44g/mol
(18.8 g CO2) / (44.00964 g CO2/mol) x (1 mol C/ 1 mol CO2) =0.427 mol C
Molar mass of H2O:
2*1+16 = 18g/mol
As there is 2 moles of H in H2O,
So,

(6.75 g H2O) / (18.01532 g H2O/mol) x (2 mol H / 1 mol H2O) = 0.74mol H 

Divide both number of moles by the smaller number of moles: 
As Smaaler no moles is 0.427:
So,
Dividing both number os moles by 0.427 :
(0.427 mol C) / 0.427 = 1.000 
(0.74 mol H) / 0.427 = 1.733 

To achieve integer coefficients, multiply by 2, then round to the nearest whole numbers to find the empirical formula:
C = 1 * 2 = 2
H = 1.733 * 2 =3.466
So , the empirical formula is C2H3

4 0

3 years ago

Read 2 more answers