Answer:
108.6 g
Explanation:
- 2NaN₃(s) → 2Na(s) + 3N₂(g)
First we use the <em>PV=nRT formula</em> to <u>calculate the number of nitrogen moles</u>:
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 0 °C ⇒ 0 + 273.2 = 273.2 K
<u>Inputting the data</u>:
- 1.00 atm * 56.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.2 K
Then we <u>convert 2.5 moles of N₂ into moles of NaN₃</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:
- 2.5 mol N₂ *
= 1.67 mol NaN₃
Finally we <u>convert 1.67 moles of NaN₃ into grams</u>, using its <em>molar mass</em>:
- 1.67 mol * 65 g/mol = 108.6 g
1000 is the answer to the queshtion
Answer:
- 1a) BaClO₃(s) → BaCl₂(g) + O₂(g)
- 1b) Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)
- 1c) Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)
- 2a) Calcium hydroxide and hydrogen gas
- 2b) Tin(II) silicate and Lead(IV) permanganate
- 2c) Magnesium oxide and water
- 2f) Calcium chloride and iodine
- 2g) Strontium phosphite and cesium nitride
- 2h) Carbon dioxide, water, and sulfur dioxide
- 2i) Iron oxide(III) and carbon dioxide
- 2j) Magnesium acetate and hydrogen gas
Explanation:
1. For each of the following, convert the word equation into a formula equation, BUT do not balance!
a) Barium chlorate → Barium chloride + Oxygen
<u>1. Chemical formulas</u>
Barium chlorate:
- It is a salt: an ionic compound.
- Barium has oxidation state +2
- Chlorate is the ion ClO₃⁻
- Swap the oxidation numbers to write the subscripts: 2 goes to ClO₃ and 1 goes to Ba
- Chemical formula Ba(ClO₃)₂
- It is solid: Ba(ClO₃)₂(s)
Barium chloride:
- It is a salt: an ionic compount
- Barium has oxidation state +2
- Chlorine is in oxidation state -1
- Swap the numbers to write the subscripts: 2 goes to Cl and 1 goes to Ba
- BaCl₂
- It is solid BaCl₂(s)
Oxygen:
- It is a diatomic gas molecule
- O₂(g)
<u />
<u>2. Write the unbalanced molecular equation:</u>
- BaClO₃(s) → BaCl₂(s) + O₂(g)
b) Chlorine + Potassium nitride → Nitrogen + Potassium chloride
<u>1. Chemical formulas</u>
Chlorine:
- It is a diatomic gas molecule
- Cl₂(g)
Potassum nitride
- Potassium has oxidation state +1
- Nitrogen is with oxidation state +3
- Swap the oxidation states
- K₃N
- It is solid: K₃N(s)
Nitrogen:
- It is a diatomic gas
- N₂(g)
Potassium chloride
- It is a salt (ionic compound)
- Potassium has oxidation state +1
- Chlorine is in oxidation state -1
- Swap the oxidation numbers
- KCl
- It is solid: KCl(s)
<u>2. Write the unbalanced molecular equation</u>
<u />
- Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)
c) Sodium nitride + Aluminum bromate → Aluminum nitride + Sodium bromate
<u>1. Chemical formulas</u>
Sodium nitride
- It is a salt (ionic compound)
- Sodium has oxidation state +1
- Nitrogen is with oxidation state -3
- Swap the oxidation numbers
- Na₃N
- It is in aqueous solution
- Na₃N (aq)
Aluminum bromate
- Salt
- Aluminum has oxidation state +3
- Bromate is the ion BrO₃⁻
- Swap the oxidation states
- Al(BrO₃)₃ (aq)
Aluminum nitride
- Both Al and N have oxidation state 3, which simply
- AlN(s). It is not soluble in water.
Sodium bromate
<u>2. Write the unbalanced molecular equation</u>
- Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)
<h2>
This is a long answer with more than 5,000 charaters; thus, I have to add the rest of the explanations on a separate file.</h2><h2>
</h2><h2>
The attached file contains the complete answer.</h2>
Answer: A. The compound CuCl is 500 times less soluble in sea water than it is in pure water.
pure water.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in a equilibrium reaction, the equilibrium will shift in a direction so as to minimize the effect.
Thus when a common ion is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing.


When common ion such as
from NaCl in sea water is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing i.e. in the left side and thus solubility of CuCl further decreases.
Answer:
Potassium and iodine!
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