Why does a reaction slow down with time?

If you have an aqueous solution that contains 1.5 moles of hcl, how many moles of ions are in the solution? (a) 1.0, (b) 1.5, (c

Darya [45]

If you have an aqueous solution that contains 1.5 moles of HCl, the number of moles of ions in the solution is 3.0 moles.

<h2>Further Explanation </h2><h3>Strong acids </h3>

Strong acids are types of acids that undergo complete dissociation to form ions when dissolved in water.
Examples of such acids are, HCl, H2SO4 and HNO3
Dissociation of HCl

HCl + H₂O ⇔ H₃O⁺ + OH⁻

<h3>Weak acids </h3>

Weak acids are types of acids that undergo incomplete dissociation to form ions when dissolved in water.
Examples of such acids are acetic acids and formic acids.
Dissociation of acetic acid

H₃COOH ⇔ CH₃COO⁻ + H⁺; CH₃COO⁻ is a conjugate base of acetic acid.

HCl which is a strong acid that ionizes completely according to the equation;

HCl + H₂O ⇔ H₃O⁺ + OH⁻

From the equation, 1 mole of HCl produces 1 mole of H₃O⁺ ions and 1 mole of OH⁻ ions.

Therefore;

1.5 moles of HCl will produce;

= 1.5 moles of H₃O⁺ ions and 1.5 moles of OH⁻ ions.

This gives a total number ions of;

= 1.5 + 1.5

= 3 moles of ions

Keywords: Strong acid, weak acid, ions, ionization

<h3>Learn more about: </h3>

Strong acid: brainly.com/question/3239966
Weak acid; brainly.com/question/3239966
Ionization of acids and bases: brainly.com/question/11844503

Level: High school

Subject: Chemistry

Topic: Salts, Acids and Bases

6 0

3 years ago

Read 2 more answers

A student reacts 5.0 g of sodium with 10.0 g of chlorine and collect 5.24 g of sodium chloride. What is the percent yield of thi

Ede4ka [16]

Answer: The percent yield of this combination reaction is 41.3 %

Explanation : Given,

Mass of $Na$ = 5.0 g

Mass of $Cl_2$ = 10.0 g

Molar mass of $Na$ = 23 g/mol

Molar mass of $Cl_2$ = 71 g/mol

First we have to calculate the moles of $Na$ and $Cl_2$ .

$\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}$

$\text{Moles of }Na=\frac{5.0g}{23g/mol}=0.217mol$

and,

$\text{Moles of }Cl_2=\frac{\text{Given mass }Cl_2}{\text{Molar mass }Cl_2}$

$\text{Moles of }Cl_2=\frac{10.0g}{71g/mol}=0.141mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation will be:

$2Na+Cl_2\rightarrow 2NaCl$

From the balanced reaction we conclude that

As, 2 mole of $Na$ react with 1 mole of $Cl_2$

So, 0.217 moles of $Na$ react with $\frac{0.217}{2}=0.108$ moles of $Cl_2$

From this we conclude that, $Cl_2$ is an excess reagent because the given moles are greater than the required moles and $Na$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NaCl$

From the reaction, we conclude that

As, 2 mole of $Na$ react to give 2 mole of $NaCl$

So, 0.217 mole of $HCl$ react to give 0.217 mole of $NaCl$

Now we have to calculate the mass of $NaCl$

$\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl$

Molar mass of $NaCl$ = 58.5 g/mole

$\text{ Mass of }NaCl=(0.217moles)\times (58.5g/mole)=12.7g$

Now we have to calculate the percent yield of this reaction.

Percent yield = $\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

Actual yield = 5.24 g

Theoretical yield = 12.7 g

Percent yield = $\frac{5.24g}{12.7g}\times 100$

Percent yield = 41.3 %

Therefore, the percent yield of this combination reaction is 41.3 %

4 0

4 years ago

A sample of wine consists of water, sugar, some amount of ethyl alcohol, and grape juice. These ingredients blend together unifo

NeTakaya

Answer: The sample of wine could be described as numbers 1, 3 & 4

Explanation:

It is a mixture because it is the physical combination of two or more substances

It is a homogeneous mixture because any solid, liquid, or gaseous mixture that has the same proportions of its components throughout any given sample is regarded as a homogeneous mixture

It is a solution because it is a special type of homogeneous mixture composed of two or more substances

7 0

3 years ago

A rectangular block of solid carbon (graphite) floats at the interface of two immiscible liquids.

Sergio039 [100]

Explanation:

Let us take the volume of block is x.

Since, the block is floating this means that it is in equilibrium. Formula to calculate net force will be as follows.

$F_{net} = Buoyancy force(F_{b}) - weight force(w)$