1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GaryK [48]
3 years ago
8

How do alpha particles compare to gamma rays?

Chemistry
2 answers:
Luba_88 [7]3 years ago
8 0

Answer:

Unlike alpha and beta particles, which have both energy and mass, gamma rays are pure energy. Gamma rays are similar to visable light, but have much higher energy. Gamma rays are often emitted along with alpha or beta particles during radioactive decay.

Explanation:

Fofino [41]3 years ago
5 0

Answer:

Unlike alpha and beta particles, which have both energy and mass, gamma rays are pure energy. Gamma rays are similar to visible light, but have much higher energy. Gamma rays are often emitted along with alpha or beta particles during radioactive decay.

-Radiation basics.

Explanation:

You might be interested in
Consider the two electron arrangements for neutral atoms A and B. What is the atomic number of A?
Andreas93 [3]
Your answer is B: The outer electron of Adam B has moved to a higher energy state
8 0
3 years ago
An experiment has been set up to determine if different types of insulation wrap will affect the temperature of water in a conta
kozerog [31]
Insulation wraps because independent is the variable you are changing to affect the dependent variable (what you are measuring)
3 0
3 years ago
4. How many grams of ammonium carbonate are needed to decompose in order to produce
Thepotemich [5.8K]

Answer:

14.23g of (NH4)2CO3

Explanation:

We'll begin by writing the balanced equation for the reaction.

(NH4)2CO3 –> (NH4)2O + CO2

Next,, we shall determine the mass of (NH4)2CO3 that decomposed and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of (NH4)2CO3 = 2[14+(4x1)] + 12 + (16x3)

= 2[14 +4] + 12 + 48

= 2[18] + 60 = 96g/mol

Mass of (NH4)2CO3 from the balanced equation = 1 x 96 = 96g

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g.

Summary:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Finally, we can determine the mass of (NH4)2CO3 that decomposed to produce 6.52g of CO2 as follow:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Therefore, Xg of (NH4)2CO3 will decompose to produce 6.52g of CO2 i.e

Xg of (NH4)2CO3 = (96 x 6.52)/44

Xg of (NH4)2CO3 = 14.23g

Therefore, 14.23g of (NH4)2CO3 is needed to produce 6.52g of CO2.

4 0
3 years ago
True or false.  The greater the distance that the plane moves from an object, the lower the force that will be applied when the
Nadya [2.5K]

Answer:

I think its false-

Explanation:

4 0
3 years ago
Read 2 more answers
Chlorine dioxide is used as a disinfectant and bleaching agent. In water, it reacts to form chloric acid (HClO3),
Sliva [168]
All done no worries

5 0
3 years ago
Other questions:
  • What is the wavelength of a wave having a frequency of 3.76x10^14
    7·1 answer
  • Name: Date:
    11·1 answer
  • What quantity of heat is required to raise the temperature of 460g of aluminum from 15C to 85C?
    5·1 answer
  • what is the boiling point of the element aluminum?
    8·1 answer
  • 2nh3(l) → nh4+(am) + nh2−(am) where (am) represents solvation by ammonia. at the boiling point (−33°c), kam = 5.1 × 10−27. calcu
    14·1 answer
  • Urgent need help fast<br> Explain what happens to the temperature of ice while it melts
    15·2 answers
  • How do you calculate bonding capacity in chemistry?
    8·1 answer
  • Glucose has formula C6 H12 O6.<br>Calculate the number of Oxygen atoms present in 18 g of glucose​
    9·2 answers
  • Name three instructions that DNA provides to a cell
    11·2 answers
  • Can someone help me find the total of the calories and grams?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!